Syntax for displaying query results as hyperlink.

[mank1]

Here's the code:

<?php
$con = mysql_connect("host","user","pass");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("theDB", $con);

$result = mysql_query("SELECT * FROM theTable");

while($row = mysql_fetch_array($result))
  {
  //$site = $row['siteName'];
  //$url = $row['siteURL'];
  //echo "<a href='$url'>$site[/url]";
  echo $row['siteName'] . " " . $row['siteURL'];
  echo "<br />";
  }
mysql_close($con);
?>

As is, the script returns, for example:
Adobe http://www.adobe.com

As you've already guessed, my problem is with the three lines that are currently commented out.
What is the proper syntax for the echo <a> tag?

[hvle]

try this, replace the 3 lines commented out with these:

$site = $row['siteName'];
$url = $row['siteURL'];
echo "<a href=\"$url\">$site</a>";

[AndyB]

[code]echo "<a href='". $row['siteURL']. "'>". $row['siteName']. "</a><br/>";[/code]

[mank1]

Thanks.

[code]echo "<a href=\"$url\">$site[/url]";[/code]
Returned a blank page. It looks like it should work, and now I'm curious why it doesn't.
Did I mis-type something?

[code]echo "<a href='". $row['siteURL']. "'>". $row['siteName']. "</a><br />";[/code]
Returned a list hyperlinks. Right on.

I should've posted this yesterday. All the countless hours wasted.

Thanks again.

[hvle]

[code]
this message board some how, changed  </a> to [/url]
[/code]

I had to put the comment inside a code block.  hmmm

[mank1]

Actually, that was what I originally posted.
I, too, now see the purpose of using the Insert Code feature, though.

Anyway, I tested your modified example, and it works. Thanks.