Bopo Posted March 23, 2009 Share Posted March 23, 2009 Hi everyone Well basically I am allowing user to comment on pages, these are obviously stored in a MySQL DB with an ID and date, however I want there to be a combo box to show comments after certain periods of time e.g Today Yesterday Past 7 Days Month All Basically I'm struggling on the logic of how the sql query will work, I suppose turning back todays date by X amount depending on which of the options are select above could logically work, but I don't know how to write it Help appreciated. Quote Link to comment Share on other sites More sharing options...
taquitosensei Posted March 23, 2009 Share Posted March 23, 2009 something along these lines $sql="select field1,field2 from table where date_format(datecolumn,'%Y-%m-%d') > '".date("Y-m-d", strtotime("-7 days"))."'"; would get you all the posts in the past 7 days "-1 Days" would get you yesterday "-30 Days" would get you last 30 days this would get last months $sql="select field1,field2 from table where date_format(datecolumn,'%Y-%m-%d')='".date("Y-m",strtotime("-1 Month"))."'"; Quote Link to comment Share on other sites More sharing options...
gnawz Posted March 23, 2009 Share Posted March 23, 2009 MySQL DATE() functions.... Simple, effective and stable DATESUB(); CURDATE(); DAY(); MONTH(); YEAR(); You can play with these Examples I have used here: <? // XXXXXXXXXxDAYS //$day being a variable for number of days... $sql = "SELECT * FROM yourdb WHERE DATE_SUB(CURDATE(),INTERVAL '$day' DAY) <= datefieldtosubtractfrom"; ?> // XXXXXXXXXX MONTH // $month being month number from 1 t0 12 $sql = "SELECT * FROM yourdb WHERE MONTH(dbfield) = '$month' AND YEAR(dbfield) = YEAR(CURDATE())"; // XXXXXXX YEAR $sql = "SELECT * FROM yourdb WHERE DATE_SUB(CURDATE(),INTERVAL '$year' YEAR) <= dbfield"; I'm sure this will help Quote Link to comment Share on other sites More sharing options...
Bopo Posted March 23, 2009 Author Share Posted March 23, 2009 Thanks for the useful posts, I'm getting a script error regarding a different line or than the sql query, and I'm 99% confident that the query is causing the problem, could someone look at my code and tell me where I'm going wrong, thanks. <?php if(isset($_POST['submit'])) { $getdate = $_POST['days']; $todaysdate = date("m.d.y"); if($getdate = "20day") { $day = 30; $sql = "SELECT * FROM comments WHERE date(CURDATE(), INTERVAL '$day' DAY) <= $todaysdate"; //date = column field in table echo $sql; } include("blogconnect.php"); $query = mysql_query($sql, $connect); while ($row = mysql_fetch_assoc($query)) { echo $row['id'] . '<br /><br />'; echo $row['comments'] . '<br /><br />'; } } ?> Quote Link to comment Share on other sites More sharing options...
Bopo Posted March 24, 2009 Author Share Posted March 24, 2009 Can I get an opinion on if that looks correct, I can't find many examples to compare to sadly. Quote Link to comment Share on other sites More sharing options...
taquitosensei Posted March 25, 2009 Share Posted March 25, 2009 this if($getdate = "20day") { $day = 30; $sql = "SELECT * FROM comments WHERE date(CURDATE(), INTERVAL '$day' DAY) <= $todaysdate"; //date = column field in table echo $sql; } should be this if($getdate == "20day") { $day = 30; $sql = "SELECT * FROM comments WHERE date(CURDATE(), INTERVAL '$day' DAY) <= $todaysdate"; //date = column field in table echo $sql; } as a comparison the equals sign needs to be a double or if you're also comparing type it's a triple. Not sure about the syntax on the query. Quote Link to comment Share on other sites More sharing options...
gnawz Posted March 26, 2009 Share Posted March 26, 2009 I do not see your db field Try <?php if(isset($_POST['submit'])) { $getdate = $_POST['days']; $todaysdate = date("m.d.y"); if($getdate = "20day") { $day = 30; $sql = "SELECT * FROM comments WHERE date(CURDATE(), INTERVAL '$day' DAY) <= your db field to compare with"; //date = column field in table echo $sql; } include("blogconnect.php"); $query = mysql_query($sql, $connect); while ($row = mysql_fetch_assoc($query)) { echo $row['id'] . '<br /><br />'; echo $row['comments'] . '<br /><br />'; } } ?> Quote Link to comment Share on other sites More sharing options...
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