[SOLVED] trouble outputting an array

[dadamssg]

writing a register script and im checking if the username and email they typed in already exists, if it does put an error message in an array, then on the form output those errors...i used the same method and it works but now its not. it just displays "array" instead of whats in the array

 

part in the register script

 

/* check whether email already exists */

$cxn = mysqli_connect($host,$user,$passwd,$dbname) or die("Couldn't connect"); 
     $sql = "SELECT email FROM Member 
                    WHERE email = '$email'";  
     $result = mysqli_query($cxn,$sql)
               or die("Couldn't execute select query.");
     $num = mysqli_num_rows($result);                 
     if ($num > 0)                                    
     {
        $alert[] = "There is already an account under $email.<br>";
	extract($_POST);
        include("register_form.php");
        exit();
     }

 /* check whether login name already exists */
     $sql = "SELECT loginName FROM Member 
                    WHERE loginName = '$username'";  
     $result = mysqli_query($cxn,$sql)
               or die("Couldn't execute select query.");
     $num = mysqli_num_rows($result);                 
     if ($num > 0)                                    
     {
        $alert[] = "$username is already in use. 
                         Select another Username.<br>";
    extract($_POST);
        include("register_form.php");
        exit();
     }

 

and the part in displaying the form and error messages if set

if(isset($alert))
   {
   echo "$alert<br>";
   }

[dadamssg]

oh forgot this part in the register script...kinda important haha

 

 if(@is_array($alert))
  {
    $aler_t = "";
    foreach($alert as $value)
     {
	 $aler_t .= $value;
	 }
   
          extract($_POST);
          include("register_form.php");
          exit();
      }

[dadamssg]

nevermind...i realized i was just checking two things and scratched the array and just used seperate variables..thanks anyway!