matfish Posted July 21, 2006 Share Posted July 21, 2006 Hi,Im trying to find out how to calculate the correct age from a given date of birth. I did use just the years (this year 2006 - date pf birth year) but this is inaccurate as surely it should also go by day and month?Anyone help?Thanks Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/ Share on other sites More sharing options...
hackerkts Posted July 21, 2006 Share Posted July 21, 2006 At the moment I could only thinks of a troublesome method.First include this to your script[code]$day = date('d'); // This will check the current date$month = date('m'); // This will check the current month$year = date('Y'); // This will check the current year[/code]After that you just include a form that let the user choose their date of birth and use those informations above to calculate.Example:[code]$_POST['year'] - $year[/code]This will give you the year. Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61545 Share on other sites More sharing options...
brown2005 Posted July 21, 2006 Share Posted July 21, 2006 <?phpfunction age($dob){$date = strtotime($dob);$today = strtotime(date("d/m/Y"));echo floor(($today - $date) / 31556926);}age("30/03/1900"); //Displays 20?> Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61546 Share on other sites More sharing options...
Barand Posted July 21, 2006 Share Posted July 21, 2006 Ummm, That would have been right in 1920. Unix time functions don't work on dates before '1970-01-01'Try[code]<?phpfunction age($dt) { $y1 = date('Y', strtotime($dt)); $y2 = date('Y'); $md1 = date('md', strtotime($dt)); $md2 = date('md'); return ($md2 < $md1) ? ($y2 - $y1 - 1) : ($y2 - $y1);}$dob = '1949-01-22';echo age($dob);?>[/code] Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61549 Share on other sites More sharing options...
brown2005 Posted July 21, 2006 Share Posted July 21, 2006 well that wasnt my own code, it was the code someone else gave to me, so i will change it to your code..SO NOT MY FAULT Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61606 Share on other sites More sharing options...
brown2005 Posted July 21, 2006 Share Posted July 21, 2006 how would you add months on to it...say like 18 years 4 months....any ideas? Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61607 Share on other sites More sharing options...
zq29 Posted July 21, 2006 Share Posted July 21, 2006 [quote author=Barand link=topic=101345.msg401042#msg401042 date=1153472554]Ummm, That would have been right in 1920. Unix time functions don't work on dates before '1970-01-01'[/quote][quote author=brown2005 link=topic=101345.msg401128#msg401128 date=1153484750]well that wasnt my own code, it was the code someone else gave to me, so i will change it to your code..SO NOT MY FAULT[/quote]That is a variation of some code I posted the other week, looking back on it, it's not the most ideal solution (there's a bug in there too I have noticed). But it does work on dates prior to the epoc on some installs. Negative timestamps are supported on a *NIX/PHP5 combo I believe... Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61621 Share on other sites More sharing options...
Barand Posted July 21, 2006 Share Posted July 21, 2006 [code]function age($dt) { $t = strtotime($dt); $y1 = date('Y', $t); $y2 = date('Y'); $md1 = date('md', $t); $md2 = date('md'); if ($md2 < $md1) { $yrs = ($y2 - $y1 - 1); $mths = 12 + date('m') - date('m', $t); } else { $yrs = ($y2 - $y1); $mths = date('m') - date('m', $t); } return "$yrs years $mths months";}[/code] Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61630 Share on other sites More sharing options...
matfish Posted July 21, 2006 Author Share Posted July 21, 2006 Barands code:[code]<?phpfunction age($dt) { $y1 = date('Y', strtotime($dt)); $y2 = date('Y'); $md1 = date('md', strtotime($dt)); $md2 = date('md'); return ($md2 < $md1) ? ($y2 - $y1 - 1) : ($y2 - $y1);}$dob = '1949-01-22';echo age($dob);?>[/code]works a treat!Many thanks!!!! Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61699 Share on other sites More sharing options...
Barand Posted July 21, 2006 Share Posted July 21, 2006 [quote=SA]That is a variation of some code I posted the other week, looking back on it, it's not the most ideal solution (there's a bug in there too I have noticed). But it does work on dates prior to the epoc on some installs. Negative timestamps are supported on a *NIX/PHP5 combo I believe...[/quote]Looks as though it works even on windows so long at its year 1901+. Guess the earlier example using 1900 was just unlucky. Link to comment https://forums.phpfreaks.com/topic/15229-calculating-age/#findComment-61738 Share on other sites More sharing options...
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