pagedrop Posted April 6, 2009 Share Posted April 6, 2009 Hello, I have this code below to grab a given file name into the server. I would to know and learn how to put a input box for this code, so the user can place any file url and the same file will be copied. thank you <?php echo "script started\n"; echo "<br>"; $inputfile = fopen("http://www.google.com/homepage.css", "r"); $outputfile = fopen("homepage.css", "w"); echo "opened files\n"; echo "<br>"; $data = ''; while (!feof($inputfile)) { $data .= fread($inputfile, 8192); } echo "read data\n"; echo "<br>"; fwrite($outputfile, $data); echo "transfered data\n"; echo "<br>"; fclose ($inputfile); fclose ($outputfile); echo "files closed\n"; echo "<br>"; echo "done"; echo "<br>"; ?> Link to comment https://forums.phpfreaks.com/topic/152707-file-grabber-problem/ Share on other sites More sharing options...
corbin Posted April 6, 2009 Share Posted April 6, 2009 http://www.tizag.com/phpT/postget.php Link to comment https://forums.phpfreaks.com/topic/152707-file-grabber-problem/#findComment-801912 Share on other sites More sharing options...
pagedrop Posted April 6, 2009 Author Share Posted April 6, 2009 Hello, thank you for the reply. I have tried and the post and get methods, but was unable to retrieve a file from a input text field using the above php code. May be i was coding not correct, can you please modify the above code? thank you Link to comment https://forums.phpfreaks.com/topic/152707-file-grabber-problem/#findComment-801935 Share on other sites More sharing options...
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