yakoup46 Posted April 12, 2009 Share Posted April 12, 2009 <html> <title>File Test</title> <body> <form action="<? echo $HTTP_SERVER_VARS['PHP_SELF']; ?>" method="post"> Enter Number <input type="text" name="number"> <input type="submit"> </form> <?php include("values.php"); $i = @$_POST['number']; if(empty($i)) echo "Enter Number Please"; else while($i<50) { if($i%2==0 && $i%5==0) echo $i . $divis_2_5 ."<br />"; else if($i%2==0) echo $i . $even_number . "<br />"; else if($i%5==0) echo $i . $divis_5 . "<br />"; else echo $i . "<br />"; $i++; } ?> </body> </html> In this script the entered number in the form is assigned a value based on the if statements. However, the script only works if $i is less than 50 (hence: $i<50). I want any value to be entered and the script will count up that number and assign the the variables according the if statements just as before. So basically I want the script to do the exact same thing except that I don't want a bound on the $i. Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 increment a separate variable instead of $i... $i = $_POST['number']; while ($x < 50) { //code here $x += $i; } Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 That only makes it so that when i enter a number it does that number only. I want it so that if i enter 4 it assigns the values(from the if statements) for 1, 2, 3, and 4. Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 can you give an example of what you want your code to look like or what you want the output to look like, if you enter in a specific number (like 4) Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 yeah just a min ill get it set up Quote Link to comment Share on other sites More sharing options...
jackpf Posted April 12, 2009 Share Posted April 12, 2009 Pardon my intrusion, but like this possibly? <?php $i = $_POST['number']; for($ii = 0; $ii <= $i; $ii++) { //do your stuff. } ?> Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 Sorry Jack that didn't seem to help. :-\ Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 Okay Crayon: So there is a form, and in that form in the input box and when I press submit with the number 5 entered. The php goes through and starts from 1 and goes to 5. and for each number is assign a value. Like it assigns "big" for 5 and then "medium" for 3, so on and so forth. At this point my script will assign the values exactly this way except that I have to set the limit to a number like 50 and press 1 for it to count to 50 and assign the values. I want to be able to type 50 and have it count to 50. Get what i mean? Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 so..you just want it to count from 1 to $i instead of 1 to 50? $i = $_POST['number']; while ($x < $i) { //code here $x++; } Quote Link to comment Share on other sites More sharing options...
jackpf Posted April 12, 2009 Share Posted April 12, 2009 Isn't that pretty much what I put..? ??? Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 okay lol. i am sure this is a problem on my end. So here is a very detailed description. [ 4 ]{Submit} 1 = small 2 = medium 3 = big 4 = large *that is what i want it to do. MINE DOES THIS [ 1 ]{Submit} |i have to put a bound like 4| 1 = small 2 = medium ect... I WANT THE FIRST WAY. i have the assigning values part down. I hope this helps Quote Link to comment Share on other sites More sharing options...
jackpf Posted April 12, 2009 Share Posted April 12, 2009 I don't understand. Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 Isn't that pretty much what I put..? ??? yes. But suggesting something in a different way sometimes helps. right...so you would want to count to the posted value. So unless there's something else you aren't mentioning, you would want to do the last thing I showed (or what jack showed). Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 <html> <title>File Test</title> <body> <form action="<? echo $HTTP_SERVER_VARS['PHP_SELF']; ?>" method="post"> Enter Number <input type="text" name="number"> <input type="submit"> </form> <?php include("values.php"); $i = @$_POST['number']; if(empty($i)) echo "Enter Number Please"; else while($x < $i) { if($i%2==0 && $i%5==0) echo $i . $divis_2_5 ."<br />"; else if($i%2==0) echo $i . $even_number . "<br />"; else if($i%5==0) echo $i . $divis_5 . "<br />"; else echo $i . "<br />"; $x++; } ?> </body> </html> okay that is my script. if i enter 4. it display 4 big 4 big 4 big 4 big. Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 Okay well in the rest of your script that relied on $i being incremented before, you need to replace that with $x because that's the thing being incremented now. Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 so replace all my $i with $x except for "$i = @$_POST['number'];" when i do that i get a bunch of undefined variables Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 so...you did this? <html> <title>File Test</title> <body> <form action="<? echo $HTTP_SERVER_VARS['PHP_SELF']; ?>" method="post"> Enter Number <input type="text" name="number"> <input type="submit"> </form> <?php include("values.php"); $i = @$_POST['number']; if(empty($i)) echo "Enter Number Please"; else while($x < $i) { if($i%2==0 && $i%5==0) echo $x . $divis_2_5 ."<br />"; else if($x%2==0) echo $x . $even_number . "<br />"; else if($x%5==0) echo $x . $divis_5 . "<br />"; else echo $x . "<br />"; $x++; } ?> </body> </html> Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 I just set $x = 1 and that solved the problem. Thank you very much. But i was wondering how this works i can really comprehend it. I am sure its simple but i just can figure it out :-\. Quote Link to comment Share on other sites More sharing options...
.josh Posted April 12, 2009 Share Posted April 12, 2009 $x is your counter. $i is what you want to count to. At the end of your while loop, $x is incremented by 1. Your while loop ($x < $i) executes until $x counts up to whatever $i is. Quote Link to comment Share on other sites More sharing options...
yakoup46 Posted April 12, 2009 Author Share Posted April 12, 2009 Oh duh. lol thank you very much Quote Link to comment Share on other sites More sharing options...
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