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Php mysql statement

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I am doing a script with php and mysql wich i want to list the orders details such as session_id, date, username and id.

To do this i used select distinct session_id from orders

cause i have 2 orders with the same session_id but i also want to list the username, date and id.

Since i used to distinct only the session_id it will only print on the screen the session id's.

I tryed "select Distinct session_id, username, date,id from orders" but in this case since some fields has diferent values even having the same session_id it will list all the results on the table.

Is there anyway of using the select statement to select all the fields and distinguish the session_id so that i can avoid duplicated session id's on the results?

If someone can help me i appreciate

Many thanks to all

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Do you mean
$sql = "select session_id, username, date,id
from orders
order by session_id";
$res = mysql_query($sql) or die(mysql_error());

$last_sid = '';
echo '<table border="1">';
while (list($sid, $usr, $dt, $id) = mysql_fetch_row($res)) {
    $sess = ($sid==$last_sid) ? '&nbsp;' : $sid;
    echo "<tr><td>$sess</td>
    $last_sid = $sid;
echo '</table>';

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