[SOLVED] Echoing Variables incorrectly due to bad structure

[aeafisme23]

Basically I am having difficulties structuring my code. I want to echo out a variable only if it meets the criteria (a password) if it does not then the average user would never know that it existed. I tried rearranging the code a few times but I am back to square one.

 

End result i get : Your name is and your phone number is:  the variables are not assigned because its being called before the variables are set... i understand this, if i put it after the if code then everyone can see it, i just want password people to see it. Any ideas? Thanks so much.

 

<?php 
$kvcc = "Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it";
?>

<?php
if ($password == "xxx1"){ 
$name = "Rick Baggot"; 
$phone = "not available";
echo $kvcc;
} 
elseif ($password == "xxx2"){ 
$name = "Richard Burnett"; 
$phone= "not available";
echo $kvcc;
} 	

?>

[taquitosensei]

try this

<?php 
if ($password == "xxx1"){ 
$name = "Rick Baggot"; 
$phone = "not available";
} 
elseif ($password == "xxx2"){ 
$name = "Richard Burnett"; 
$phone= "not available";
}    
echo "Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it";

[jkewlo]

Try this. Not sure if it will work as I have not tested it.

<?php
if ($password == "xxx1"){ 
$name = "Rick Baggot"; 
$phone = "not available";
echo $kvcc;
} 
elseif ($password == "xxx2"){ 
$name = "Richard Burnett"; 
$phone= "not available";
echo $kvcc;
}   

$kvcc = "Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it";
?>

 

[aeafisme23]

Thanks for the replies, unfortunately the first one is not what I am wanting to do jkewlo you tried exactly what I did but that does not work from what i found.

 

 

HOWEVER, this did work:

 

<?php
if ($password == "ccrab1"){ 
$name = "Randy Bennett"; 
$phone = "not available";
$kvcc = "Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it";
echo $kvcc;
} 
elseif ($password == "ccrab2"){ 
$name = "Richard Burnett"; 
$phone= "not available";
$kvcc = "Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it";
echo $kvcc;
} 	
?>

 

The only thing i do NOT like about this is it's very redundant to have to repost the variable $kvcc numerous times....surely there is a way to get it to work logically like this. I did solve my problem but I am still not happy with having to waste more resources than are necessary...if anyone has an idea I would be much appreciative.

 

 

[MatthewJ]

why not just do this?

 

<?php

$password = "ccrab1";

if ($password == "ccrab1"){ 
$name = "Randy Bennett"; 
$phone = "not available";
} 
elseif ($password == "ccrab2"){ 
$name = "Richard Burnett"; 
$phone= "not available";
}

echo "Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it";    

?>

[kenrbnsn]

Turn it into a function:

<?php
function echoit($name,$phone) {
    return("Your name is $name and your phone number is: $phone This is all pertinent information for all 
that correctly logged in, no one else should be able to see it");
}
switch ($password) {
    case 'ccrab1':
         $kvcc = echoit('Randy Bennett','not available');
         break;
    case 'ccrab2':
         $kvcc = echoit('Richard Burnett','not available');
         break;
}
echo $kvcc;
?>

 

Ken

[mrMarcus]

what was wrong with your original post compared to your last post?  there is absolutely no need to repeatedly set $kvcc in every statement.

 

as long as the contents of $kvcc are the same, set it (once) and forget it.