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Hello,

 

I have a modal window that appears, but it will only accept html files. No big deal, so i thought.

 

Is it possible to write a function that will render out a php file behind the scenes and grab all it's contents.

 

ie.

 

script.php

<?php echo 'This Works';

 

If i were to use fopen or get_file_contents nothing would show up.

 

I would like php to do it's magic and return "This Works".

 

Any ideas?

 

Thanks,

envex (matt)

What you're looking for is eval.

 

http://us3.php.net/eval

 

I don't think it's working, i'm getting:

 

Parse error: syntax error, unexpected '<' in /nfs/c03/h04/mnt/57152/domains/wheresyourstore.com/html/test.php(5) : eval()'d code on line 1

 

The file i'm referencing is reference.php

 

my modal window will grab reference.php, but it won't parse any of the php because of the way it deals with javascript loading the content.

Well, shit.

 

I was expecting the PHP file you uploaded to be purely php. In this case it has a mix of both?

 

Yeah, sorry it's been a long day of back and forth. The old brain is a bit fried.

 

The reference file has no syntax errors, when i view it by itself it renders everything fine.

 

This stupid modal box is causing a major headache, and of course it's on a friday :P

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