hank9481 Posted May 11, 2009 Share Posted May 11, 2009 I have a table of 30 different ID's. I have data in each row related to a particular ID, and based on a sort menu, I want to be able to jump to each where I have a page showing the data describing the selected ID. Such as = /2018/previews.php?abbr=atl.php The problem is, I cannot figure out how to make it work. For example, when I select something in my menu, it does nothing. Here's the code. Help me! $result = mysql_query("SELECT T.name, T.nickname, HM.first_name, HM.last_name, S.mgr, TR.w, TR.l, P.grade, P.in, P.out, P.x_player, P.x_text, P.bo_player, P.bo_text, P.spec_hit, P.spec_hit_text, P.spec_pitch, P.spec_pitch_text, P.question, P.review, P.year, P.outlook, P.proj, P.l1, P.l2, P.l3, P.l4, P.l5, P.l6, P.l7, P.l8, P.l9, P.sp1, P.sp2, P.sp3, P.sp4, P.sp5, P.rp FROM previews P JOIN abbr A ON P.team_id=A.team_id JOIN teams T ON P.team_id=T.team_id JOIN human_managers HM ON P.team_id=HM.team_id JOIN staffs S ON P.team_id=S.team_id JOIN team_record TR ON P.team_id=TR.team_id WHERE A.abbr=".$abbr." LIMIT 1") or die(mysql_error()); while ($row = @mysql_fetch_array($result,MYSQL_ASSOC)) { Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/ Share on other sites More sharing options...
RussellReal Posted May 11, 2009 Share Posted May 11, 2009 ok.. jesus christ that is 1 seriously extended sql.. but you don't have single quotes encasing your abbr do: '{$abbr}' instead of ".$abbr." and I'm not sure if u can do all those joins :S but if u can than go for it..but u prolly dun rly need to join all those tables =\ Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/#findComment-831325 Share on other sites More sharing options...
hank9481 Posted May 11, 2009 Author Share Posted May 11, 2009 Believe me, I'm no expert, but that didn't work. Here's the link: http://mblsim.com/Season%20Previews/2018/previews.php?abbr=atl Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/#findComment-831328 Share on other sites More sharing options...
hank9481 Posted May 11, 2009 Author Share Posted May 11, 2009 Correction. It did work! Thanks very much! Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/#findComment-831338 Share on other sites More sharing options...
RussellReal Posted May 11, 2009 Share Posted May 11, 2009 not to be a stickler but please click the 'Topic Solved' option lol.. it just eerks me sometimes :$ Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/#findComment-831424 Share on other sites More sharing options...
hank9481 Posted May 14, 2009 Author Share Posted May 14, 2009 Having another issue, hoping to get help. My page above now works, but I am working on creating a webform to input data. Here's the PHP Info- //ASSIGN FORM VALUES $team_id=$_POST["team_id"]; $review=$_POST["review"]; $outlook=$_POST["outlook"]; $x_player=$_POST["x_player"]; $x_text=$_POST["x_text"]; $bo_player=$_POST["bo_player"]; $bo_text=$_POST["bo_text"]; $year=$_POST["year"]; $spec_hit=$_POST["spec_hit"]; $spec_hit_text=$_POST["spec_hit_text"]; $spec_pitch=$_POST["spec_pitch"]; $spec_pitch_text=$_POST["spec_pitch_text"]; $proj=$_POST["proj"]; $in=$_POST["in"]; $out=$_POST["out"]; $l1=$_POST["l1"]; $l2=$_POST["l2"]; $l3=$_POST["l3"]; $l4=$_POST["l4"]; $l5=$_POST["l5"]; $l6=$_POST["l6"]; $l7=$_POST["l7"]; $l8=$_POST["l8"]; $l9=$_POST["l9"]; $sp1=$_POST["sp1"]; $sp2=$_POST["sp2"]; $sp3=$_POST["sp3"]; $sp4=$_POST["sp4"]; $sp5=$_POST["sp5"]; $rp=$_POST["rp"]; $grade=$_POST["grade"]; $question=$_POST["question"]; //INSERT DATA mysql_query("UPDATE previews SET team_id='$team_id', review='$review', outlook='$outlook', x_player='$x_player', x_text='$x_text', bo_player='$bo_player', bo_text='$bo_text', year='$year', spec_hit='$spec_hit', spec_hit_text='$spec_hit_text', spec_pitch='$spec_pitch', spec_pitch_text='$spec_pitch_text', proj='$proj', in='$in', out='$out', l1='$l1', l2='$l2', l3='$l3', l4='$l4', l5='$l5', l6='$l6', l7='$l7', l8='$l8', l9='$l9', sp1='$sp1', sp2='$sp2', sp3='$sp3', sp4='$sp4', sp5='$sp5', rp='$rp', grade='$grade', question='$question' WHERE team_id='{$team_id}'"); //CLOSE OUT CONNECTION mysql_close($dbh); ?> Can someone help me? Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/#findComment-833732 Share on other sites More sharing options...
mikr Posted May 14, 2009 Share Posted May 14, 2009 It looks to me like you are using some reserved keywords. I think in and out are both reserved keywords (google mysql reserved keywords and the first on the list will take you to a mysql page showing a list of such). The simple solution is to put backwards quotes ( ` ) around each field name ie( instead of review='$review' have `review`='$review' ). Also, as an aside, I sure hope you are validating your input, because else, you're leaving your db wide open. I hope that my above comments about reserved keywords help you out. Quote Link to comment https://forums.phpfreaks.com/topic/157654-solved-where-clause-help/#findComment-833739 Share on other sites More sharing options...
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