karthikanov24 Posted May 18, 2009 Share Posted May 18, 2009 hi EVEN THOUGH I MADE mysql_free_result($result);,I AM GETTING OUT PUT FOR echo $row['id']; echo $row['email']; CAN U EXPLAIN ME HOW.?ACTUALLY WHAT IS THE OUTPUT............. /////////////////////////////////////////////////////////////// <?php $result = mysql_query("SELECT id,email FROM people WHERE id = '42'"); if (!$result) { echo 'Could not run query: ' . mysql_error(); exit; } /* Use the result, assuming we're done with it afterwords */ $row = mysql_fetch_assoc($result); /* Now we free up the result and continue on with our script */ mysql_free_result($result); echo $row['id']; echo $row['email']; ?> Quote Link to comment https://forums.phpfreaks.com/topic/158553-output-of-the-codings/ Share on other sites More sharing options...
Mark Baker Posted May 18, 2009 Share Posted May 18, 2009 You fetch the first row of the result from your query into $row, then free $result. $row is unchanged because it is a copy of the values that had been in $result before you freed up $result. Quote Link to comment https://forums.phpfreaks.com/topic/158553-output-of-the-codings/#findComment-836256 Share on other sites More sharing options...
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