[SOLVED] adding 1 to alphanumeric value

[Walker33]

I have a column that contains a string, for example, R01,R02,R03,R04,S01,S02,S03,A01,A02.  I need to isolate the last R or S or A, which my code does, but then I need to add one to that final variable.  ++ just repeats it.  Is there a simple way to do this then to split up $result ?

 

<?php
$query6 = pg_query("SELECT sublicenses FROM sublicenses WHERE license = '3RF6EWOT2'");
$getarray = pg_fetch_assoc($query6);
$license6 = $getarray['sublicenses'];
echo "$license6 <br><br>";

$string="$license6";
$domain3=strrchr($string,"S");
echo "$domain3<br><br>";
if (!$domain3){echo "no licenses<br><br>";}

$string2=split(",",$domain3);
print_r ($string2);
$result = $string2['0'];
echo "<br><br>$result";

$addstn = $result++;
echo "<br><br>$addstn";
?>

 

So my $result returns what I want, S03.  But my $addstn also returns S03.  I need a final return of S04, in this instance.  Thanks a lot for any tips!

[gevans]

I'm not sure if this will, work, but off the top of my head;

 

<?php
//This works if there are always 3 characters
$number = (int) $result[2];
$new_number = $number+1;
$result = srr_replace($number, $new_number, $result);
echo $result;

[Walker33]

Hmm.  Put it in just as you wrote it, but not getting a return for the echo.

[Walker33]

And yes, it will always be a three-digit variable, one letter, two numbers.

[gevans]

little syntax error;

 

$result = srr_replace($number, $new_number, $result);

 

should be

 

$result = str_replace($number, $new_number, $result);

[Walker33]

Beautiful!  Works like a champ.  Thank you very much.  I'm pretty new to this, so I wasn't aware of the str_replace function.  Really appreciate your help!

[Walker33]

Spoke a second too soon.  If my result is R11, your script returns R22 instead of R12.

[gevans]

Try this

 

<?php
$result = substr_replace($result, $new_number, 2);

[Walker33]

That's the ticket!  This time I tested all dup numbers, 11, 22, 33, etc.  Perfect.  Thanks again, your help is greatly appreciated.