simple if..

[pgrevents]

Its simple i know but i cannot see the errors of my ways. I am creating a sign up form and I am passing the details via ajax. I know that both variables are sending and getting picked up by the script but its returning false info.

 

Basicly its a validation to check if the user has confirmed their password correctly.

 

here is the code

 

<?php
$pass = $_POST['pword'];
$check = $_POST['check_pass'];
if ($pass == $check)
{
echo "yes";
}

else 
{
echo "no";
}
?>

 

i been staring at this machine all day thats prob why i cant see the error :0 any help??

[jackpf]

Try this

echo $pass.' - '.$check;

And see what's output.

[razta]

if ($pass === $check)

 

Maybe that will work?

[RussellReal]

<?php
$pass = $_POST['pword'];
$check = $_POST['check_pass'];
if (($pass == $check) && (strlen($pass)) {
echo "yes";
} else {
echo "no";
}
?>

 

this would be a tad more secure, however, there is no error in ur php..

 

I think you're sending them as the wrong names you're expecting

[pgrevents]

Thanks for the hints. I tried every if expresion i could think of and not working. I am sending I know they are getting recieved correctly ill try some fidgeting

[jackpf]

Try this

echo $pass.' - '.$check;

And see what's output.

 

What did that output then?

[pgrevents]

that was the first thing i done when it wasnt working its the same variables as passed

[pgrevents]

solved it was the ajax a letter out of place thanks for the help