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output of imagejpeg() function


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#1 kestas

kestas
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Posted 31 July 2006 - 05:36 AM

Hi!
Need help with imagejpeg() function. It should be outputting image to a file or a browser. Outputting to a file works fine, but when trying to output an image to the browser image is shown as a text(bunch of symbols with header in front). Is there anything that I don`t understand about it? Thanks in advance! Will include my code:

<? session_start();
$maindir="C:\web\docs\\\thumbs";
$mydir = opendir($maindir);
$exclude = array("index.php", "convert.php", "..", ".", "thumbs", "nuotr", "Thumbs.db") ;
while($fn = readdir($mydir)) {
if ($fn == $exclude[0] || $fn == $exclude[1]|| $fn == $exclude[2]||
$fn == $exclude[3]|| $fn == $exclude[4]|| $fn == $exclude[5]|| $fn == $exclude[6]) continue;
$myimage="$fn";
echo"$fn<br>";
$photo = ImageCreateFromJPEG("C:\web\docs\\thumbs\\$fn");
ImageJPEG($photo);
}
closedir($mydir);
?>




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