Jump to content

output of imagejpeg() function


kestas

Recommended Posts

Hi!
Need help with imagejpeg() function. It should be outputting image to a file or a browser. Outputting to a file works fine, but when trying to output an image to the browser image is shown as a text(bunch of symbols with header in front). Is there anything that I don`t understand about it? Thanks in advance! Will include my code:

<? session_start();
$maindir="C:\web\docs\\\thumbs";
$mydir = opendir($maindir);
$exclude = array("index.php", "convert.php", "..", ".", "thumbs", "nuotr", "Thumbs.db") ;
while($fn = readdir($mydir)) {
if ($fn == $exclude[0] || $fn == $exclude[1]|| $fn == $exclude[2]||
$fn == $exclude[3]|| $fn == $exclude[4]|| $fn == $exclude[5]|| $fn == $exclude[6]) continue;
$myimage="$fn";
echo"$fn<br>";
$photo = ImageCreateFromJPEG("C:\web\docs\\thumbs\\$fn");
ImageJPEG($photo);
}
closedir($mydir);
?>
Link to comment
https://forums.phpfreaks.com/topic/16076-output-of-imagejpeg-function/
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.