[SOLVED] PHP Shuffle

[shamuraq]

Objective:

I just need to display random color value from a list of color in an array

 

Scenario:

<?
$lebar = 10;
for ($i = 0; $i <$lebar; $i++){
$color = array('#FFFFFF','#333333');
$color = shuffle($color);
echo "$color<br>";
}
?>

Output is:

1

1

1

1

1

1

1

1

1

1

Question:

I simply want to display #FFFFFF or #333333... What went wrong in the code?

Thanx in advance...

[gevans]

were you looking for something like this?

 

<?php
$color = array('#FFFFFF','#333333');
$lebar = count($color);
shuffle($color);
for ($i = 0; $i <$lebar; $i++){
echo "{$color[$i]}<br>";
}

 

If you just wanted to alternate use the following;

 

<?php
$color = array('#FFFFFF','#333333');
$lebar = 10;
for ($i = 0; $i <$lebar; $i++){
if(!($i%2))
	echo "{$color[0]}<br>";
else
	echo "{$color[1]}<br>";
}

[kickstart]

Hi

 

Or for 10 random ones

 

<?
$lebar = 10;
for ($i = 0; $i <$lebar; $i++){
$color = array('#FFFFFF','#333333');
$color = shuffle($color);
echo $color[0]."<br>";
}
?>

 

All the best

 

Keith

[gevans]

Keith, that wont work, suffle() returns an integer and will change the array '$color' to a variable holding either a 1 or a 0 (1 for success of the shuffle())

[kickstart]

Hi

 

You right. Brain fade. Need to take the assingment back to $color out.

 

<?
$lebar = 10;
for ($i = 0; $i <$lebar; $i++){
$color = array('#FFFFFF','#333333');
shuffle($color);
echo $color[0]."<br>";
}
?>

 

All the best

 

Keith