Unexpected behavior from Imagick

[jckdnk111]

Hi,

 

I'm attempting to create a polygon cutout of an image.

I've figured out how to do it using imagemagick from the command line (convert).

Now I want to put this logic into PHP using the Imagick library but I am getting some unexpected results -- namely, I always get a black background instead of a transparent background.

 

I could call the convert commands directly using exec or something similar, but I'd much rather use the Imagick lib for better error handling and efficiency.

 

http://jckdnk.pastebin.com/m3e325705 - some sample php code along with the corresponding convert commands.

I'd really appreciate any help.

[jckdnk111]

So if no one has any ideas can you point me in the right direction?

Should I be asking PHP gurus or imagemagick gurus? How could I find out who wrote the imagemagick module for php?

 

Any idea what forums might I might hit for this type of thing?

Thanks!