Allowing "Essex" but blocking "sex"

[ArizonaJohn]

Hello,

 

The function below does a great job of blocking porn terms.  However, it also blocks words that contain porn terms, such as "Essex."  How could I allow "Essex" but block "sex", and allow "chicken breast" but block "breast", etc.?

 

Thanks in advance,

 

John

 

<?php

function check_porn_terms($input){
     $porn_terms = array("porn", "sex", "tits", "cock", "penis", "vagina", "pussy", "itakeithard", "hard_cock", "really_hard_cock", "suckmydickbitch", "fuck"); //add terms here
     foreach($porn_terms as $term){
          if(substr_count($input, $term) > 0) return false;
     }

     return true;
}

?>

[proud]

<?php


$settings['replace'] = array ("bastard" => "b******", "shit" => "s***",	"sex" => "s**");


function filter_bad_words($text) {

global $settings;

    foreach ($settings['replace'] as $k => $v)
    {
        $text = preg_replace("/\b$k\b/i",$v,$text);
    }

return $text;

}


$answer="Essex sex";

$answer = filter_bad_words($answer);

echo $answer;


?>

[Daniel0]

proud, yours is filtering, not blocking.

 

This should do:

function check_porn_terms($input) {
$porn_terms = array("porn", "sex", "tits", "cock", "penis", "vagina", "pussy", "itakeithard", "hard_cock", "really_hard_cock", "suckmydickbitch", "fuck"); //add terms here

return !preg_match('#\b(' . join('|', array_map('preg_quote', $porn_terms)) . ')\b#i', $input);
}

var_dump(check_porn_terms('essex')); // true
var_dump(check_porn_terms('sex')); // false

[gizmola]

I agree with proud that regex is the way to go,  What he has provided is powered by the  "\b" metacharacter, which in regex matches a "word boundary".  The basic regex that does the work, is actually "\b$var\b".  If you haven't used the preg_ functions before, you need to wrap the string in a begin and end character, which in his example is the "/" character.  The last "i" character is a modifier that basically says:  match case insensitively.

 

If you want to retain the strategy of your function, rather than doing replacements, this is probably closer to what you want to do:

 

function check_porn_terms($input){
     $porn_terms = array("porn", "sex", "tits", "cock", "penis", "vagina", "pussy", "itakeithard", "hard_cock", "really_hard_cock", "suckmydickbitch", "fuck"); //add terms here
      $porn_regex = array();
      foreach ($porn_terms as $term) {
          $porn_regex[] = '\b' . $term . '\b';
      }
      $porn_regex =  '/' . implode('|', $porn_regex) . '/i';
      if (preg_match($porn_regex, $input)) {
          // A bad word found
          return false;
      } else {
          // String ok
          return true;
      }     
}

 

 

Note: didn't check that this code actually works

 

In this case I make one big regex string and only invoke the regex library once, rather than invoking it for every single bad word in your list as was done in proud's snippet.  My guess is that this will be more efficient, although if you want a search/replace feature, proud's is the way to go.

[gizmola]

Well lookie at that, while I was typing Daniel did the same thing, but even more elegantly.

[ArizonaJohn]

Hi Daniel0,

 

Thanks for your response, your code works in allowing "essex" but blocking "sex."  However, I would also like to block "breast" but allow "chicken breast", etc.

 

Does anyone know a way to modify the code Daniel0 gave me to do this?

 

Thanks,

 

John

[gizmola]

There's no good solution to the issue of phrases, nor for that matter, simple variations to get around the filter.  My suggestion would be to simply focus on the extreme vulgarity.