[Java] Displaying an integer in place of a char/string

[9three]

Hey,

 

I'm creating a simple Minesweeper game in Java for school. I'm having a small issue though. I don't know how to display an integer within a char variable.

 

What I'm doing is checking the left, right, bottom and top for mines and if it's found increment the points for each mine.

 

I'm using a bi dimensional array, Table[x ][y] (table is assigned as a char) and I'm printing it out.

 

After adding all the points I want to display the points to that assigned coordinates (x, y). But I can't do Table[x ][y] == points as Table is searching for a character not an integer. I also tried doing Table[x ][y] = ' ' +points but that's a no go.

 

Is there something I can do to display the points?

[corbin]

Well the number characters are 48-57:

 

0 = 48

1 = 49

....

9 = 57

 

 

 

So as long as you're talking single digits, it's essentially (this is c++ code... you'll have to do the Java equivalent):

 

char c = '5';

int num = ((int) c) - 48;

 

 

 

 

 

 

 

 

 

(Or did I entirely misunderstand your question?)

[9three]

I can't define the variable as the numbers will dynamically by the users total points. It could range from 0 to around 200 points.

 

You get more points based on how many mines are around.

[GingerRobot]

Perhaps i also misunderstood, but aren't you essentially looking to convert an integer to a string?

 

http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Integer.html#toString()

[corbin]

I think he's trying to convert a string to an integer....

 

 

 

In which case, I'm not sure why I made it so complicated earlier....

 

 

 

Why not just do:

 

 

Int i = new Int(str);

 

 

Or what ever the Java equivalent is.