prabha_friend Posted June 29, 2009 Share Posted June 29, 2009 index.php function User_Role_Menu($Role_id) { $myrset = mysql_query("CALL SP_User_Role_Menu(".$Role_id.")"); //fetch and read and session the tabs and links for this user //A General Counter $counter = '0'; while($User_Role_Menu_Set_Row = mysql_fetch_array($myrset)) { //echo $User_Role_Menu_Set_Row['TAB_LINK']; - Guruji $_SESSION['Tabs'][$counter]=$User_Role_Menu_Set_Row['TAB_NAME']; $_SESSION['Links'][$counter]=$User_Role_Menu_Set_Row['TAB_LINK']; echo $counter; $counter = $counter+1; } } something.php <?php $MYOBJ->User_Role_Menu($_SESSION['ROLE_ID']); ?> why this generates this error „Warning: Cannot use a scalar value as an array“? Where's the problem whats the remedy. Dear Friends. Please dont suggest to do in any other way. I am very curious about the errors I am getting while i work even though I achieved it by some other way. I still wants to understand. Thanks in advance. Quote Link to comment Share on other sites More sharing options...
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