[SOLVED] preg_split

[didgydont]

is it possible to do some thing like this ?

$chars = preg_split("/([a-z0-9]{3})([a-z0-9]{2})/", $str);

i found this but it gets to messy for what i want to do

$v = array();
for($x=0;$x<strlen($str);$x++){
                $v[] = $str[$x];}

[Adam]

Well yeah it's possible, but what are you trying to do??

[didgydont]

make this smaller

trying to convert this 530pm to $1 = 5 $2= 30 $3=pm

this works for now but i want to make it tiny

function b4ampm($b4apptime){
if(ereg("^[a-z0-9]{5}$", $b4apptime)){
$b4a = preg_split('//', $b4apptime, -1, PREG_SPLIT_NO_EMPTY);
return $b4a[3] . $b4a[4] ;}
if(ereg("^[a-z0-9]{6}$", $b4apptime)) {
$b4a = preg_split('//', $b4apptime, -1, PREG_SPLIT_NO_EMPTY);
return $b4a[4] . $b4a[5] ;}
}

function b4mins($b4apptime){
if(ereg("^[a-z0-9]{5}$", $b4apptime)){
$b4a = preg_split('//', $b4apptime, -1, PREG_SPLIT_NO_EMPTY);
return $b4a[1] . $b4a[2] ;}
if(ereg("^[a-z0-9]{6}$", $b4apptime)) {
$b4a = preg_split('//', $b4apptime, -1, PREG_SPLIT_NO_EMPTY);
return $b4a[2] . $b4a[3] ;}
}

function b4hour($b4apptime){
if(ereg("^[a-z0-9]{5}$", $b4apptime)){
$b4a = preg_split('//', $b4apptime, -1, PREG_SPLIT_NO_EMPTY);
return $b4a[0] ;
}
if(ereg("^[a-z0-9]{6}$", $b4apptime)) {
$b4a = preg_split('//', $b4apptime, -1, PREG_SPLIT_NO_EMPTY);
return $b4a[0] . $b4a[1] ;
}
}

[Adam]

What are the possible formats it could be? 24hour possible? leading zeros possible? etc. You certainly don't need all that...

 

Perhaps something like:

 

$str = '530pm';

preg_match('/(0?[0-9]|1[0-2])(0?[0-9]|[1-5][0-9])(am|pm)/i', $str, $matches);

print_r($matches);

 

Can make it more accurate once we know all the possible formats though...

[.josh]

is 530pm really the format you are working with? So what happens when it is 123pm or the like?  is it 1:23pm? 12:30pm? 12:03pm?  You can't accurately regex something like that.

[didgydont]

thanx guys all possible formats are like so

"900am", "915am", "930am", "945am", "1000am", "1015am", "1030am", "1045am", "1100am", "1115am", "1130am", "1145am", "1200pm", "1215pm" and so on

thats why i had if(ereg("^[a-z0-9]{5}$", $b4apptime)) and if(ereg("^[a-z0-9]{6}$", $b4apptime))

 

i used your help to do this an example

 

$str = "1245pm";

if(ereg("^[a-z0-9]{5}$", $str)){

preg_match('/([0-9]{1})([0-9]{2})(am|pm)/', $str, $matches);}

if(ereg("^[a-z0-9]{6}$", $str)){

preg_match('/([0-9]{2})([0-9]{2})(am|pm)/', $str, $matches);}

print_r($matches);

answer = Array ( [0] => 1245pm [1] => 12 [2] => 45 [3] => pm )

 

wich will shrink the codes lots but i dont under stand why the array put in the original value ?

 

 

 

[Adam]

Realise this is closed now but, you could improve that further:

 

if (strlen($str) == 5)
{
    $pattern = '/([0-9]|1[0-2])(0[0-9]|[1-5][0-9])(am|pm)/';
}
elseif (strlen($str) == 6)
{
    $pattern = '/(1[0-2])(0[0-9]|[1-5][0-9])(am|pm)/';
}

preg_match($pattern, $str, $matches);

[didgydont]

thank you very much