php view image

[ctcp]

i got this script...

<?
$URL_parts = @parse_url ($row_DetailRS1['site_url']);
$DOMAIN = str_ireplace ("www.", "", $URL_parts['host']);
?>
<img src="image/site/<?if ( @is_file ("image/site/".$DOMAIN.".jpg" ) ){ echo $DOMAIN.".jpg"; }else{ echo "unknow.jpg"; }?>" alt="" width="270" height="173" /></p>

 

how to

in site_url colume i got links

http://www.google.gr/mplamplampla

http://www.phpfreaks.com/forums/index.php?action=post;board=1.0

http://www.gmail.com/mplamplampla

 

now.. if site_url find google.gr show google.gr.jpg

if find nothink show unknow.jpg

if find google.gr and phpfreaks.com

show google.gr.jpg and phpfreaks.com.jpg

 

 

thanks for help ..

 

 

[Adam]

Really basic explanation there.

 

if find google.gr and phpfreaks.com

show google.gr.jpg and phpfreaks.com.jpg

 

How exactly would this data look if both were found? How would you 'show' both, using 2 images? Do you *only* find google.gr / phpfreaks.com / gmail.com / nothing, or is the list endless? Need more information to help you.

[ctcp]

thank you mate for your help

look here (and sorry for my english )

http://linkscopy.com/

 

now scan only the first line from site_url i whant scann all lines

and if finde difrent domain show it as jpg

 

look here maybe you understant ..

 

http://linkscopy.com/

 

[Adam]

Well then you were on the right tracks before. Why doesn't it work at the moment? Remove the "@" suppressing the error, could explain why it's not working.

 

if find google.gr and phpfreaks.com

show google.gr.jpg and phpfreaks.com.jpg

 

I'm still at a loss as to this though, couldn't see anything similar on that website.

[ctcp]

look

i got 1) result page

      2) view page

in result page i display name

 

in view page display name and site_url

 

now in result page i whant display

name and image

image = site_url domain ..

 

<?php
$URL_parts = @parse_url ($row_DetailRS1['site_url']);
$DOMAIN = str_ireplace ("www.", "", $URL_parts['host']);
?>
<img src="image/site/<?if ( @is_file ("image/site/".$DOMAIN.".jpg" ) ){ echo $DOMAIN.".jpg"; }else{ echo "unknow.jpg"; }?>" alt="" width="270" height="173" /></p>

 

this working fine ... but if in site_url i got 2 links this script display only the first line

(script reading only the first line from colum site_url)

example

if i got in site_url

google.gr/mplampla  and  phpfreaks.com/forums/

this script will take google.gr.jpg

i whant now if site_url got

google.gr/mplampla

and phpfreaks.com/forums/

view google.gr.jpg

and phpfreaks.com.jpg

 

 

 

[Adam]

How would this look within the database though, literally "google.gr/mplampla  and  phpfreaks.com/forums/"??

[ctcp]

google.gr/mplampla432456

google.gr/mplampla432434545

phpfreaks.com/forums/

phpfreaks.com/forums/3

phpfreaks.com/forums/23

like this ..