[SOLVED] hiding login/pass boxes once logged in HELP

[shane85]

I just want to say thanks in advance...this website has been EXTREMELY helpful in getting me through everything...im new to this but quickly learning and agian, thnx in advance.

 

I have attatched an image of my login/pass fields....the html is as follows

 

<div id="login_box">

 

<form id="loginForm" name="loginForm" method="post" action="login-exec.php">

   

    <fieldset>

        <p>Username:</p>

            <input type="text" id="user"  class="png_bg"/>

        </fieldset>

       

        <fieldset>

        <p>Password:</p>

            <input type="password" id="pass" class="png_bg" />

        </fieldset>

        <fieldset>

        <button id="login_btn" type="submit"></button>

        </fieldset>

       

</form>

<!--#login--></div>

 

very straight forward... what I would like to do is once the user is logged in and the session is created, to kill that text...I had a website done in the past which used a template file and I was able to put a tag before the above html like

 

<!-- BEGIN login -->

 

and after i twas done, end it with

 

<!-- END login -->

 

it was very easy and straight forward...what would the best way to achieve this be without using this template file? Basically I want it so when a user is logged in, the login fields arent there to see, or to re-login...might as well just take them out

 

thanks again

 

[attachment deleted by admin]

[phpwiz]

i didn't read your code into detail but what i did was make an if statement. if the user is logged in displayect ect. if not logged in display  login form

 

 

 

[oni-kun]

I'm sure what every website does (atleast mine), uses PHP to echo the box in the first place.. roughly like..

 

if ($SESSION['loggedin'] == false) { 
echo '<input type="textarea">blaa</input>';// Whatever HTML your login form has
} else {
  echo "You are logged in as <b>".$SESSION['login_name']." <a href=\"logout.php\">log out</a></b>"
}

 

.. So it'd only appear when they're not logged in.

[shane85]

oni-kun - thanks alot for reply to both of my threads...your going above and beyond! hate to bug you again, I tried it, and have it displayed like so in the login_include file

 

<?php

 

if ($SESSION['loggedin'] == false) {

echo '

 

<div id="login_box">

    <form id="loginForm" name="loginForm" method="post" action="login-exec.php">

   

    <fieldset>

        <p>Username:</p>

            <input name="login" type="text" class="png_bg" id="login" />

        </fieldset>

       

        <fieldset>

        <p>Password:</p>

    <input name="password" type="password" class="png_bg" id="password" />

        </fieldset>

        <fieldset>

        <button id="login_btn" type="submit"></button>

        </fieldset>

       

    </form>

</div>

 

';// Whatever HTML your login form has

} else {

  echo ""; // if its logged in, I dont want it to display anything in this area

}

 

but what I log in, it is still there...what do I need to include in my login script for this to work? I have included a snipit from my login script that registers variables into the session....what do I need to change? again...thank you

 

session_regenerate_id();

$member = mysql_fetch_assoc($result);

$_SESSION['SESS_LOCATION_ID'] = $member['location_id'];

$_SESSION['SESS_COMPANY_NAME'] = $member['company_name'];

$_SESSION['SESS_ADDRESS'] = $member['address'];

$_SESSION['SESS_CITY'] = $member['city'];

$_SESSION['SESS_PROVINCE'] = $member['province'];

$_SESSION['SESS_POSTAL_CODE'] = $member['postal_code'];

$_SESSION['SESS_FIRST_NAME'] = $member['contact_firstname'];

$_SESSION['SESS_LAST_NAME'] = $member['contact_lastname'];

$_SESSION['SESS_CONTACT_PHONE'] = $member['contact_phone'];

$_SESSION['SESS_CONTACT_EMAIL'] = $member['contact_email'];

$_SESSION['SESS_COMPANY_LOGO'] = $member['company_logo'];

$_SESSION['SESS_TICKER'] = $member['ticker'];

session_write_close();

header("location: venue.php");

exit();

[shane85]

I SOMEWHAT got it to work...it takes it out....I have it like

 

<?php

 

if ($SESSION['$_SESSION['SESS_LOCATION_ID']' == false) {

echo '

 

<div id="login_box">

    <form id="loginForm" name="loginForm" method="post" action="login-exec.php">

   

    <fieldset>

        <p>Username:</p>

            <input name="login" type="text" class="png_bg" id="login" />

        </fieldset>

       

        <fieldset>

        <p>Password:</p>

    <input name="password" type="password" class="png_bg" id="password" />

        </fieldset>

        <fieldset>

        <button id="login_btn" type="submit"></button>

        </fieldset>

       

    </form>

</div>

 

';// Whatever HTML your login form has

} else {

  echo ""; // if its logged in, I dnot want it to display anything in this area

}

 

?>

 

 

but am getting this error

 

Parse error: syntax error, unexpected T_STRING, expecting ']' in /home/content/website/_include_login.php on line 3

[oni-kun]

That works great, you did a simple error there though..

This:

if ($SESSION['$_SESSION['SESS_LOCATION_ID']' == false) {

Needs to be changed into:

if (!isset($_SESSION['SESS_LOCATION_ID'])) {

? You seemed to have accidentally nested invalid sessions,  but 'a'b'c'd' would show as an error, quote wise.

isset() should be as well instead of '==false'.. !isset() would mean if not set, aka not in the session..

[shane85]

HA! it works!! Thank you very much...again, this board is great...great members

[oni-kun]

HA! it works!! Thank you very much...again, this board is great...great members

 

No problem Be sure to mark this topic as solved, in the bottom left of the thread..