[SOLVED] confused using json, array

[simon551]

<?php $query_rsAdmin = ("SELECT users.empId,  COALESCE(users.HRAdmin, 0) AS hradminv, COALESCE(users.DivisionAdmin, 0) AS divadminv, COALESCE(users.GlobalAdmin, 0) AS globaladminv, COALESCE(users.travelAdmin,0) AS traveladminv, COALESCE(users.projectAdmin, 0) AS projectadminv, COALESCE(users.accountingadmin, 0) AS accountingadminv, tblgroups.divisionId FROM users Inner Join tblemployees ON users.EmpID = tblemployees.EmpID Inner Join tblgroups ON tblemployees.groupId = tblgroups.groupId WHERE users.EmpID = $empid");
$rs = mysql_query($query_rsAdmin, $conn_org) or die(mysql_error());

$arr = array();

while($obj = mysql_fetch_object($rs)) {
$arr[] = $obj;
}
$arr[]="'koala'->1"; 

echo json_encode($arr);
?>

returns:

[{"empId":"18","hradminv":"0","divadminv":"1","globaladminv":"0","traveladminv":"0","projectadminv":"0","accountingadminv":"0","divisionId":"1"},"'koala'->1"]

 

but I want it to return

[{"empId":"18","hradminv":"0","divadminv":"1","globaladminv":"0","traveladminv":"0","projectadminv":"0","accountingadminv":"0","divisionId":"1","koala":"1"}]

 

I'm lost.

 

 

[Daniel0]

Instead of

$arr[]="'koala'->1";

do

$arr[0]->koala ='1';

[simon551]

gracias!