meltingpoint Posted August 15, 2009 Share Posted August 15, 2009 I am searching an array for instances of words or partial words. I need to have the regular expression check to make sure that there is a -space- at the beginning. This way- it will not count matches of the string in the middle of words. here is what I have tried; $search_var = "sil"; $match = preg_grep("/$search_var/i", $my_array); //this was the original that led me to have to check for the space at the beginning. // //so I tried; $match = preg_grep("/^([:space:])$search_var/i", $my_array);//DID NOT WORK I know I am making a stupid error- but for the life of me- I cannot figure it out. Quote Link to comment https://forums.phpfreaks.com/topic/170440-solved-regular-expression-preg_grep/ Share on other sites More sharing options...
oni-kun Posted August 15, 2009 Share Posted August 15, 2009 If you're wanting to match a space before search term.. $match = preg_grep("/^\s$search_var/i", $my_array); Quote Link to comment https://forums.phpfreaks.com/topic/170440-solved-regular-expression-preg_grep/#findComment-899074 Share on other sites More sharing options...
meltingpoint Posted August 15, 2009 Author Share Posted August 15, 2009 Thanks for that. I was also experimenting and found that using b\ works too. Example; $match = preg_grep("/\b$search_var/i", $my_array); this makes sure that the search string is at the beginning of the word Cheers Quote Link to comment https://forums.phpfreaks.com/topic/170440-solved-regular-expression-preg_grep/#findComment-899077 Share on other sites More sharing options...
oni-kun Posted August 15, 2009 Share Posted August 15, 2009 \b is the word boundry or matches white space at the beginning or end of a match, \s matching white space before just the term, which you should use if you were to match multiple spaces in some case... No problem. Quote Link to comment https://forums.phpfreaks.com/topic/170440-solved-regular-expression-preg_grep/#findComment-899082 Share on other sites More sharing options...
.josh Posted August 16, 2009 Share Posted August 16, 2009 more accurately, \b is a word boundary and will match anything not considered a "word" character, as defined by \w. \w being defined as a-z A-Z 0-9 _ and any other characters considered to be word characters defined by local settings. So basically, \b$search_var will match if there is a space before, it, but it will also match if there is any other non-alphanumerical character before it. Also, \b only matches at where you put it. \b$search_var does not match at the beginning and end of $search_var; it just looks for a non-word character at the beginning. If you want it to match at the beginning and end, you would do \b$search_var\b just like anything else. Using \s is preferred, however, note that \s is shorthand for "whitespace" characters, not just a space made from the spacebar. It will also match tabs and newline characters. If you want to only match a space and nothing else, you would use a physical space in your regex: $match = preg_grep("/ $search_var/i", $my_array); Quote Link to comment https://forums.phpfreaks.com/topic/170440-solved-regular-expression-preg_grep/#findComment-899482 Share on other sites More sharing options...
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