phpwiz Posted August 20, 2009 Share Posted August 20, 2009 ok i have made a script with bbcodes and emoticons and it all works perfectly but i need a php code where it inserts the selected option into the text area. what i mean to say is. on top of when u post a topic or reply on phpfreaks forum there are buttons and stuff that u can click and it enters the [][/] stuff for you i am trying to make this does anyone know how or can they teach me please because i need this ASAP!!!!! Quote Link to comment Share on other sites More sharing options...
trq Posted August 20, 2009 Share Posted August 20, 2009 Don't double post. Go google javascript WYSIWYG editors, there are plenty. This has absolutely nothing to do with PHP Coding Help! Quote Link to comment Share on other sites More sharing options...
phpwiz Posted August 20, 2009 Author Share Posted August 20, 2009 Ok i tried to get one to work and it didnt, here is the entire code <?php session_start(); ?> <script language="JavaScript"> var Editor; function Format(action) { Editor.execCommand(action, false, null); } function Colour(colour) { Editor.execCommand("forecolor",false, colour); } window.onload = function() { Editor = document.getElementById('textbox').contentWindow.document; Editor.designMode = "on"; document.forms[0].onsubmit = function() { var text = document.getElementById('text'); text.value = Editor.body.innerHTML; } } </script> <?php include "BBcode.php"; include "admin.php"; $connect = mysql_connect('localhost', 'root', '') or die("Couldnt connect"); mysql_select_db('members') or die("Couldn't find db"); $namecheck = mysql_query("SELECT username FROM users"); $count = mysql_num_rows($namecheck); if ($_SESSION['username']) { if ($_POST ['post']) { //get data $title = $_POST ['title']; $body = $_POST ['body']; $date = $_POST ['date']; $postee = $_SESSION['username']; $avatar = $_POST ['avatar']; //check for existance if ($title&&$body&&$avatar) { $date = date ("Y-m-d"); //insert data $insert = mysql_query("INSERT INTO news VALUES ('','$title','$body','$date','$postee','$avatar')") or die (mysql_error ()); echo "Your news has been posted! <a href='v_news.php'>News here.</a>"; } else { echo "Please fill out title and body!<p>"; } } else { ?> <form action='p_news.php' method='POST'> <table> <tr> <td> <input type="button" onclick="Format('[b]TEXT HERE[/b]')" value="Bold" /> <input type="button" onclick="Format('[u]TEXT HERE[/u]')" value="Underline" /> <input type="button" onclick="Format('[i]TEXT HERE[/i]')" value="italics" /> <input type="button" onclick="Format('[s]TEXT HERE[/s]')" value="Strike" /> <input type="button" onclick="Format('[url=http://URL HERE]LINK[/u]')" value="Url" /> <input type="button" onclick="Format('[img=IMG LINK HERE]')" value="Img" /> <input type="button" onclick="Format('[color=blue]TEXT HERE[/color]')" value="Color" /> </td> </tr> </table> <table> <td> Title: </td> <td> <input type='text' name='title'><p> </td> </tr> <tr> <td> Avatar: </td> <td> <input type='text' name='avatar'><p> </td> </tr> <tr> <td> Body:<br> </td> <td> <iframe id="textbox" style="width:300px; height:150px"></iframe><br/> </td> </tr> <tr> <td> </td> <td> <input type='submit' name='post' value='Post this news!'> </td> </tr> </table> </form> <?php } } else die("Sorry you are not logged in <a href='login.php'> Click here</a> to login"); ?> Quote Link to comment Share on other sites More sharing options...
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