dachshund Posted August 25, 2009 Share Posted August 25, 2009 Hi, I'm just trying to enter the user's id into a comments table when they post a comment. but it's posting it in twice each time. any ideas why? <?php include "template/header.php"; if($_SESSION['uid']){ $userid=$_SESSION['uid']; $sql="INSERT INTO `comments`(`userid`) VALUES ('$userid');"; $result=mysql_query($sql) or die(mysql_error()); if($result){ echo "Successful\n"; } else { echo "ERROR\n"; } }else { session_destroy(); echo "You must be logged in to add a comment.\n"; } ?> <?php include "template/footer.php"; ?> Quote Link to comment Share on other sites More sharing options...
alexdemers Posted August 25, 2009 Share Posted August 25, 2009 Nothing wrong with that code. What's in your header.php file? Quote Link to comment Share on other sites More sharing options...
dachshund Posted August 25, 2009 Author Share Posted August 25, 2009 this is my header.php <?php session_start(); $connect= mysql_connect ("", "", "") or die(mysql_error()); $db = mysql_select_db ("", $connect); $session_name = $_SESSION['uid']; ?> <head> <script type="text/javascript" src="/phptesting/csspopup.js"></script> <link href="/phptesting/template/stylesheet.css" rel="stylesheet" type="text/css" /> <title></title> </head> <body marginheight="0"> <div id="site_container"> <!-- sign up --> <div id="toolbar"> <div id="follow"> <ul> <li><img src="/facebook_icon.png"></li> <li><img src="/twitter_icon.png"></li> <li><img src="/myspace_icon.png"></li> <li><img src="/rss_icon.png"></li> </ul> </div> <ul> <li> <?php if($session_name){ echo "<span class=\"login_text\"><a href=\"/phptesting/account/\">ACCOUNT</a> | <a href=\"/phptesting/logout.php\">LOGOUT</a></span>\n"; }else { ?> <?php include $_SERVER['DOCUMENT_ROOT'] . "/phptesting/template/loginform.php"; ?> </li> <li> <?php include $_SERVER['DOCUMENT_ROOT'] . "/phptesting/register.php"; } ?> <li> <form action="/phptesting/search.php" method="get" class="search_text" name="search" id="searchform" > <input type="text" size="30" class="search_text" value="SEARCH" name="q" onFocus="if(!this._haschanged){this.value=''};this._haschanged=true;"/> </form> </li> </ul> </div> <!-- end --> <div class="clear"></div> <div id="header"> HUH. Magazine </div> <!-- Navigation --> <div id="navigation"> <ul> <li><a href="/phptesting/">Home</a></li> <li><a href="/phptesting/feature/">Features</a></li> <li><a href="#">Interviews</a></li> <li><a href="#">Reviews</a></li> <li><a href="#">Blog</a></li> <li><a href="#">Shop</a></li> <li><a href="#">TV</a></li> </ul> </div> <div class="clear"></div> Quote Link to comment Share on other sites More sharing options...
dachshund Posted August 25, 2009 Author Share Posted August 25, 2009 and when i do: $sql="INSERT INTO `comments` (`userid`, `comment`) VALUES ('$session_name', '$commentsbox');"; it only ads the enters data into the 'comment' column on the first post it creates. Quote Link to comment Share on other sites More sharing options...
dachshund Posted August 25, 2009 Author Share Posted August 25, 2009 help! this is driving me mad Quote Link to comment Share on other sites More sharing options...
mikesta707 Posted August 25, 2009 Share Posted August 25, 2009 I'm not sure you are supposed to have a semi-colon at the end of SQL queries but I might be wrong... Quote Link to comment Share on other sites More sharing options...
dachshund Posted August 25, 2009 Author Share Posted August 25, 2009 yeah i got rid of that but still the same. Quote Link to comment Share on other sites More sharing options...
dachshund Posted August 25, 2009 Author Share Posted August 25, 2009 any way to fix this anyone? it's got me stumped Quote Link to comment Share on other sites More sharing options...
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