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[SOLVED] Syntax help


defeated

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Seems a little trivial creating 3 variables out of an array in that sense, but I'm assuming there's a reason behind it. I don't believe you can concatenate two variables together in that way to form a variable variable, you need to create the variable name first and then use that to create the variable variable, like so:

 

$var_name = $jobloc.($i + 1);
$$var_name = $addjobloc[$i];

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