[SOLVED] array_search for loop question.

[JMair]

<?php

$todo = array( 
1 => "9AM Wake Up.",
2 => "10AM Drink make hot tea.",
3 => "11AM Finish reading CNET news.",
4 => "12AM Shower and get dressed.",
5  => "1PM Finish watering the garden.",
6  => "2PMTake a nap.",
7  => "3PM Dream about something fantastic.",
8  => "4PM Wake up from nap.",
9  => "5PM Go to work.",
);


for ($i = 1; $i <= 20 ; $i++) { // notice the 20 in order to see the whole readout of array_search.
	//echo $i ."<br>";
	$key = array_search($i, $todo); 
	echo $key ."<br>";

}//end of for

?>

 

Print out is exactly.

 

5

6

7

8

9

 

 

 

1

2

3

4

 

What would be causing this?

 

[Alex]

What are you expecting/trying to get?

[JMair]

1

2

3

4

5

6

7

8

9

I get that when I do

echo $i ."<br>";

I'm just unsure why

the following doesn't give it in order and adds additional <br> instead.

$key = array_search($i, $todo); 
	echo $key ."<br>";

 

I'm just trying to understand it is all really.

[KevinM1]

Reading the documentation on array_search() may come in handy.  It explains why you're getting your results.

[JMair]

I did before I posted but didnt see anything direct enough for me I suppose. I'll check again. Thanks guys.

 

Also, I have to add, I've learned about as much or more from this forum than I have from my PHP book and a class I took a while ago. Thanks for the help again.

[KevinM1]

I did before I posted but didnt see anything direct enough for me I suppose. I'll check again. Thanks guys.

 

Also, I have to add, I've learned about as much or more from this forum than I have from my PHP book and a class I took a while ago. Thanks for the help again.

 

array_search() searches an array's values.  The first instance of the value '1' is the 5th element of the array, whose value is "1PM Finish watering the garden."