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Hi all

 

I have the following

 

if(getramdoms(2) != 0)
{
$rr = $rr. '1,';
}
if(getramdoms(44) != 0)
{
$rr = $rr. '2,';
}
if(getramdoms(99) != 0)
{
$rr = $rr. '3,';
}
if(getramdoms(132) != 0)
{
$rr = $rr. '4,';
}

print $rr;

 

which produces something like

 

1,3,4,

 

My question is, how can I randomly pick one of those values and set the random value as

 

$randomnumber = ?

 

any help would be great as im totally stumped

 

thanks very much for any help

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https://forums.phpfreaks.com/topic/172513-solved-picking-random/
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I have tried using

 

$exploded = explode(",", "$rr");
$rand = rand(1, count($exploded));
echo $exploded[$rand];

 

which kinda works, it displays a random number, but sometimes returns nothing (although it could be 0 it's returning)

 

any ideas why it would do that?

You need to redo how you are creating the values. By concatentating the values into single string with a comma at the end, you are making this more difficult than it needs to be. If you explode the values like Mark suggests you will alwaus have an empty value at the end of the array.

 

Create your values in an array to begin with and then just use array_rand() to get a random value out of that array

 

$rr = array();

if(getramdoms(2) != 0) { $rr[] = 1; }
if(getramdoms(44) != 0) { $rr[] = 2; }
if(getramdoms(99) != 0) { $rr[] = 3; }
if(getramdoms(132) != 0) { $rr[] = 4; }

$randomnumber = array_rand($rr);

when picking just one entry with array rand, it returns the key of the array, not the value at that key, so the last line to

 

print $rr[$randomnumber];

Yeah, I missed adding that - thanks for the assist. Could also do this

 

$randomnumber = $rr[array_rand($rr)];

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