[SOLVED] super newbie project, trying to use array attributes in a function but get error

silverglade · September 7, 2009

hi, my teacher told me to use an array to control the look of a table. and im trying, but have no idea if this is valid code. i also get the error

Parse error: parse error, expecting `')'' in C:\wamp\www\lessons\table\table.php on line 46

please, any advice or help greatly appreciated. thank you. derek

here is the code

<?php

//table options multidimensional array

$table_options = array(
	'color'=>array(
			'color1'=> 'blue',
			'color2'=> 'green',
			'color3'=> 'red',
			'color4'=> 'orange',
			'color5'=> 'purple',
			'color6'=> 'yellow'


			), 
	'width'=>array(
			'width1' => '20%',
			'width2' => '50%',
			'width3' => '70%',
			'width4' => '90%',
			'width5' => '100%'

			),
	'border'=>array(
			'border1' => '0',
		    'border2' => '1'

			),

	 'row_num'=>array(
	         'rows1'=> '1',
			 'rows2'=> '2',
			 'rows3'=> '3',
			 'rows4'=> '4',
		     'rows5'=> '5'
			 )
	);




///setting and outputting the table functions

//declaring the array attributes as the function arguments.

function table_setter($table_options['color'][],$table_options['width'][],$table_options['border'][], $table_options['row_num'][]){ 

          ///youre altering the table dimensions with php!!!
$table .= "<table background-color=\"$table_options['color'][]\"  width=\"$table_options['width'][]\" border=\"$table_options['border'][]\" >
					<tr>
					<td>header 1</td>
					<td>header 2</td>
					<td>header 3</td>
					</tr>";



for($i=0;$i<$table_options['row_num'][];$i++){


		$table .= "<tr>
					<td>data</td>
					<td>data</td>
					<td>data</td>
					</tr>";

}

$table .= "</table>";


return $table;

}


echo table_setter($table_options['color']['color1'],$table_options['width']['width3'],$table_options['border']['border2'], $table_options['row_num']['rows5']); 



?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
</body>
</html>

bundyxc · September 7, 2009

Check again to make sure that you properly closed each of your arrays.

silverglade · September 7, 2009

thank you, i just checked pretty close and all of my arrays are closed properly i think. any more help appreciated. if you can thanks. derek

Alex · September 7, 2009

You shouldn't be passing arguments like that.. Look up the proper way.

silverglade · September 7, 2009

im googling for the proper way to pass arguments, and i know how to pass arguments into a function, but not the proper way to use an array. i cant find out what my problem is in this code. and the error as well.

TeNDoLLA · September 7, 2009

You cant pass argument like $table_options['color'][] <-- See you are not giving any index, how you think the program will know what you try to pass? You should pass e.g $table_settings['color'] and then use the table with indexes inside the function.

Example

<?php
$testArray = array('blue', 'green', 'red');

// define test function.
function printColors($colors)
{
    // Manual way.. (not good way)
    echo $colors[0] . '<br/>';
    echo $colors[1] . '<br/>';
    echo $colors[2] . '<br/>';

    // Dynamic way
    foreach ($colors as $color)
    {
        echo $color  . '<br/>';
    }

    // Another way..
    echo implode('<br/>', $colors);
}

// Then calling the function.

// WRONG
printColors($testArray[]);

// RIGHT
printColors($testArray);

Hope that helps.. not sure though.

silverglade · September 7, 2009

thank you very much. i think i totally misunderstood the assignment. thank you for posting that code. i understand it. so thanks. im ditching this assignment i think because using the array is no different than just using function parameters typed in (hardcoded).

TeNDoLLA · September 7, 2009

In PHP, pretty much yes.

.josh · September 7, 2009

No you almost had it right the first time. You have your array of options, then when you call your function you pass individual elements, just like you did. But in your actual function construct, you would have variables, and you would use those variables in the function. Example:

function table_setter($color,$width,$border,$row_num){ 
  // now use $color, $width, $border, $row_num 
}

$table = table_setter($table_options['color']['color1'],etc....);

TeNDoLLA · September 7, 2009

Yes but my point being that you can't pass argument like this: someFunction($array[]).

.josh · September 8, 2009

$array[] by itself creates a new (array) element.

You cannot use it as part of a function argument construct:

// can't do this
function someFunction($array[]) {
  ..
}

Also, you cannot do this:

// can't do this
function someFunction($var) {
  ..
}

someFunction($array[]);

But you CAN do this:

// can't do this
function someFunction($var) {
  ..
}

someFunction($array[] = 'something');

because ultimately you are passing just the value 'something' as an argument.

silverglade · September 8, 2009

great thank you very much for that

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[SOLVED] super newbie project, trying to use array attributes in a function but get error

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