[SOLVED] Array help please!

[Pioden]

Hi folks,

 

As a results of an ldap search I have an array (or maybe more than one) which I can't figure out how to process.

 

The output of print_r ($info); (where ifo is the array) gives me two results which look like this:

 

Array ( [count] => 2 [0] => Array ( [uid] => Array ( [count] => 1 [0] => user1 ) [0] => uid [count] => 1 [dn] => uid=user1,ou=Users,dc=mycollege,dc=ac,dc=uk ) [1] => Array ( [uid] => Array ( [count] => 1 [0] => user2 ) [0] => uid [count] => 1 [dn] => uid=user2,ou=Users,dc=mycollege,dc=ac,dc=uk ) ) 

 

Processing the arrays with array_values

$prawf = array_values($info);
while (list($key,$value) = each($info)) {
echo "$key : $value<br />";
}

 

gets me

 

count : 2

0 : Array

1 : Array

 

which to me suggests arrays within arrays. How on earth do I process this stuff to get meaningful values i.e. user1,user2 etc.

 

All assistance very much apperiated.

 

TIA

 

Huw

[Adam]

You can use a loop within a loop, you'd be best using foreach as well, much simpler. The manual contains example of how to loop through multi-dimensional arrays with foreach.

[Garethp]

Do

 

echo "<pre>";

print_r($info);

echo "</pre>";

 

It'll help the array make more sense

[Adam]

Do

 

echo "<pre>";

print_r($info);

echo "</pre>";

 

It'll help the array make more sense

 

 

...Or just right click > view source.

[Pioden]

Wow. Thank you both - I think I'm getting somewhere now.

 

Using Gareth's suggestion I now see:

Array
(
    [count] => 2
    [0] => Array
        (
            [uid] => Array
                (
                    [count] => 1
                    [0] => user1
                )

            [0] => uid
            [count] => 1
            [dn] => uid=user1,ou=Users,dc=mycollege,dc=ac,dc=uk
        )

    [1] => Array
        (
            [uid] => Array
                (
                    [count] => 1
                    [0] => user2
                )

            [0] => uid
            [count] => 1
            [dn] => uid=user2,ou=Users,dc=mycollege,dc=ac,dc=uk
        )

)

 

using foreach

(an example dragged kicking and screaming from the manual comments)

 

foreach ($info as $v1) {

    foreach ($v1 as $v2) {

        echo "$v2<br />";

    }

}

 

the output is:

Warning: Invalid argument supplied for foreach() in /var/www/huw/ldaptest.php on line 38

Array

uid

1

uid=user1,ou=Users,dc=mycollege,dc=ac,dc=uk

Array

uid

1

uid=user2,ou=Users,dc=mycollege,dc=ac,dc=uk

 

I'm a bit puzzled why it warns about invalid arguments and then prints a result though!!

 

Can I use foreach to just access the userx value in array uid?

[Adam]

Your array spans into a third dimension, try:

 

foreach ($info as $v1) {
    foreach ($v1 as $v2) {
        if (is_array($v2)) {
            foreach ($v2 as $v3) {
                echo $v3;
            }
        } else {
            echo $v2 . "<br />";
        }
    }
}

[Pioden]

Just figured out the three dimensional thingy.

 

echo $info["0"]["uid"]["0"];

 

gives me exactly the data I need - but just for the first array. How do I loop it through the arrays to get the results?

 

foreach {

echo $info["0"]["uid"]["0"];

}

 

doesn't work. I guess I need some statement before {

 

BTW I really do appreciate your patience. I'm used to working with database results so this kind of array stuff is unknown territory!

[Adam]

Try:

 

foreach ($info as $i) {
    echo $i['uid'][0] . '<br />';
}

[Pioden]

Genius! Much appreciated.