[SOLVED] finding the name of the current page

[didgydont]

hi all

i have done a $_SERVER['PHP_SELF'] wich makes /demo/index.php but i want it so no mater what i change the folder name to i get the name of the php file only so in this case index.php any ideas ?

thank you all

[mikesta707]

$_SERVER['REQUEST_URI']

 

give that a try

[didgydont]

thank you for your promt reply but the still produces /demo/index.php

[mikesta707]

hmm post your code. request_uri should return the page you are currently running code on. I've never seen it post the actual directory you are in

[didgydont]

this i what i put in

im pretty sure when it is run in the root it produces just the file name like $_SERVER['PHP_SELF']

 echo "<br><br>Filename is: " . $_SERVER['REQUEST_URI'] ;

[Zane]

straight from the manual

http://us2.php.net/manual/en/reserved.variables.server.php

 

echo "

" .$_SERVER['REMOTE_HOST'] ." REMOTE_HOST ";

echo "

" .$_SERVER['REMOTE_PORT'] ." REMOTE_PORT ";

echo "

" .$_SERVER['SCRIPT_FILENAME'] ." SCRIPT_FILENAME ";

echo "

" .$_SERVER['SERVER_ADMIN'] ." SERVER_ADMIN ";

echo "

" .$_SERVER['SERVER_PORT'] ." SERVER_PORT ";

echo "

" .$_SERVER['SERVER_SIGNATURE'] ." SERVER_SIGNATURE ";

echo "

" .$_SERVER['PATH_TRANSLATED'] ." PATH_TRANSLATED ";

echo "

" .$_SERVER['SCRIPT_NAME'] ." SCRIPT_NAME ";

echo "

" .$_SERVER['REQUEST_URI'] ." REQUEST_URI ";

[didgydont]

thank you but

that returns "/home/mydomain/public_html/nextfolder/demo/index.php"

[Zane]

well try Script_name

 

or use the same one and enclose it with basename

basename($_SERVER['SCRIPT_FILENAME'])

[didgydont]

i already had and it returned same as $_SERVER['PHP_SELF']

[Zane]

seriously, what does your code look like

[didgydont]

<? $filename = $_SERVER['PHP_SELF'];?>
                                <br><br>the url is :<? echo $_SERVER['HTTP_HOST']; ?>
                                <br> the page is : <? echo $filename;
                                if (strpos($filename, 'index.php') !== FALSE) {echo "you are at index.php";}
                                echo "<br><br>Filename is: " . $_SERVER['SCRIPT_FILENAME'] . "<br>" . $_SERVER['SCRIPT_NAME'] ;?>

 

what about this

$filesn = str_replace('/demo/','',$_SERVER['PHP_SELF']);
                                echo "<br>final: $filesn";

is it possible to do a wild card like '%/' i know that doesnt work but just trying to show you what im trying to do.

[didgydont]

<?

this solved my problem

$Filepath = $_SERVER['PHP_SELF'];
$Filepath = preg_split('/\//', $Filepath, -1, PREG_SPLIT_NO_EMPTY);
$countarray = count($Filepath);
$countarray = ($countarray-1);
foreach ($Filepath as $key => $fileloc) {
  if ($countarray==$key){echo "$fileloc";}
}

 

 

?>