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Dear All,

 

I am new here, and I hope that my message goes in the right place; let me thank any one who will take the time to answer me, and wish much success to this board!

 

Now, let me introduce the point:

 

- I am making a website to sell discs, using PHP/MYSQL

- This issue is regarding the 'admin panel', where I created a page called 'insert_category.php' for the admin to insert a new music category.

 

Here is the code of this page :

 

<?php

// include function files for this application
require_once('disc_sc_fns.php');
session_start();

do_html_header("Adding a category");
if (check_admin_user()) {
  if (filled_out($_POST))   {
    $catname = $_POST['catname'];

    if(insert_category($catname)) {
      echo "<p>Category \"".$catname."\" was added to the database.</p>";

} else {
      echo "<p>Category \"".$catname."\" could not be added to the database.</p>";
    }
  } else {
    echo "<p>You have not filled out the form.  Please try again.</p>";
  }
  do_html_url('admin.php', 'Back to administration menu');
} else {
  echo "<p>You are not authorised to view this page.</p>";
}

do_html_footer();

?>

 

 

Other files are included to make this page run, of course :

 

The first one is the connection to the database:

 

<?php

function db_connect() {
   $result = new mysqli('localhost', 'batman', '1234', 'disc_sc');
   if (!$result) {
      return false;
   }
   $result->autocommit(TRUE);
   return $result;
}

function db_result_to_array($result) {  
   $res_array = array();

   for ($count=0; $row = $result->fetch_assoc(); $count++) {
     $res_array[$count] = $row;
   }

   return $res_array;
}

?>

 

 

Here is the function used in insert_category.php, for inserting the category into the database :

 

function insert_category($catname) {
// inserts a new category into the database

   $conn = db_connect();

   // check category does not already exist
   $query = "select * from categories where catname='".$catname."'";
   $result = $conn->query($query);
   if ((!$result) || ($result->num_rows!=0)) {
     return false;
   }

   // insert new category
   $query = "insert into categories values ('', '".$catname."')";
   
   $result = $conn->query($query);
   if (!$result) {
     return false;
   } else {
     return true;
   }
}

 

 

-------------------------------------

This is it for the background..

-------------------------------------

 

So basically, a category is inserted in my database, and I would like to get the ID after inserting a category; I tried the function mysql_insert_id(), I tried last_insert_id() too, but.. I did not work :(

 

I have been searching the solution on many websites, but I was not able to succeed :confused:

 

I found out that I had to link the mysql_insert_id() function with the 'link_identifier' : is this the solution?

How would I do this (meaning what would be my link_identifier in this case?!)

 

That is it, let me thank again all the people that will take the time to help me!

 

Cheers to the whole board...

 

Batman

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