[SOLVED] Get the number which is before the )

[newbtophp]

How would i get the numbers which are after the comma within the brackets:

 

Like for example code (the code and the variables are always different but the rule is the same):

 

$O0ghhss=fopen($Oedfdsfg00,'rb');while(--$scande354)fgets($v0o00arys,1024);fgets($O000O0O00,2036);$OO00O00O0=(base64_decode(strtr(fread($O0gfdfgdf0O00,362),'ywkhRHYKNWOUTAaBbCcDdFfGgIiJjLlMmPpQqSsVvXxZz0123456789+/=','ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/')));echo($aO0fdsf00O0);

 

The number is:

 

362

 

So the rule is the number is always before the first string within the single quotes:

 

362),'1STSTRING'

 

 

$* = Random variable, with letters (lower and upercase) and numbers.

 

1STSTRING = Random string containing letters (lowercase and uppercase), numbers, slashes, + signs and = symbols.

[cags]

Looking at the example it also contains plus and forward slash, is this a requirement?

[newbtophp]

Looking at the example it also contains plus and forward slash, is this a requirement?

 

Yes some strings contain forward slashes, some dont, some strings contain + some dont. So its literally random string but always within the same rule/requirement.

[cags]

How about something like this...

 

preg_match("/,(\d*?)\),'.*?'/", $input, $out);
echo $out[1];

[newbtophp]

Thanks Cags! That worked perfect!

 

 

Solved