[SOLVED] Array for Months of the Year

[Omzy]

Basically I have a months array:

 

$months=array('01'=>'Jan', '02'=>'Feb', '03'=>'Mar', '04'=>'Apr', '05'=>'May', '06'=>'Jun', '07'=>'Jul', '08'=>'Aug', '09'=>'Sep', '10'=>'Oct', '11'=>'Nov', '12'=>'Dec');

 

And I use a foreach loop to access this array and generate the markup as follows:

 

echo '<option value="'.$index.'"'>'.$value.'</option>';

 

As you can see the <option> VALUE attribute is 2 digits, which is why I've had to create the array with the 2 digit numbers as the index. Can this be done in a more simpler way?

[mikesta707]

i guess you could use str_pad(), like so

$arr = array("jan", "feb", "mar","april");
foreach($arr as $key=>$value){
echo '<option value="'.str_pad((int)($key+1), 2, '0', STR_PAD_LEFT).'">'.$value.'</option>';
}

 

but thats not much better... if you already have it, and it works just use it

 

oops slight edit

[kickstart]

Hi

 

Very similar to the above, and again not really simpler than your original:-

 

<?php
$months=array('Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec');
for($iCnt = 1 ; $iCnt <= 12 ; $iCnt++)
{
echo '<option value="'.sprintf('%02d',$iCnt).'">'.$months[$iCnt - 1].'</option><br />';
}
?>

 

All the best

 

Keith

[Mark Baker]

Or even drop the array

for($i = 1; $i <= 12; ++$i) {
echo '<option value="'.sprintf('%02d',$i).'">'.date('M',mktime(0,0,0,$i,1,2009)).'</option>';
}