Reading background color from other pages

[bharris]

I am building a table of links.  I would like each cell of the table to have the same background color (no images, just standard colors) of the page that is linked to in that cell.  Seems fairly simple, read the background color of the body tag on the referred to page and plug that value into the background color property of the cell.  I am just not skilled enough yet (fairly new to PHP).

 

On the surface, it seems fairly straightforward.  Is it?

 

Thanks

[Daniel0]

Actually that's in no way straightforward. There are a number of ways in which the background color may be set. You'd have to consider the bgcolor attribute on the body tag. You'd also have to consider CSS and the way selectors are given weight according to the CSS specification as well as the fact that numerous stylesheets may have conflicting information, and in that case you'll have to figure out which one should be the correct one.

[bharris]

In my case, all of the pages that I am linking to are using the background property on the body tag.  So, if I can do this without considering CSS and just looking at the body tag, is it still that complicated?

Thanks!

[Daniel0]

In that case you can do something like this (assuming $source holds the HTML source code of that page):

 

preg_match('#<body[^>]+bgcolor=[\'"]([#a-z0-9]+)[\'"][^>]*>#i', $source, $matches);
$color = $matches[1];

 

Not tested.

[bharris]

It is throwing an error but I do understand what you are doing and that helps a bunch.  I just need to look at the syntax.

 

I really appreciate your help!

[Daniel0]

Ah sorry here you go:

 

preg_match('#<body[^>]+bgcolor=[\'"]([\#a-z0-9]+)[\'"][^>]*>#i', $source, $matches);
$color = $matches[1];

 

I forgot to escape the # inside the regex.

[bharris]

This is exciting.....It is working.

 

I used

preg_match('/body bgcolor=\'([#a-z0-9]+)[\']/', $source, $matches);

 

Worked perfectly!  Thank you for the help.