need help with some php logic

[Drezek]

well im learning php and mysql i found this tutorial http://www.phpeasystep.com/workshopview.php?id=6 and i was wondering how to make the checklogin.php and main_login.php parts into the same webpage like once it sends the form information it just reloads the webpage and it registers a session and displays information from the database using the username id this is my first week into learning how to program php and mysql so feel free to educate me 

[mikesta707]

quite easy

<form>
<!-- form stuff -->
<?php

if (isset($_POST['username'])){//whatever the username input field is
//paste your login check stuff here
}
?>

 

you can either set the action of the form to the same page, OR just don't set an action at all. If you don't set an action on the form, the action will  by default be the page of the form.

 

the isset() checks of the post variable is set. and the only way the post variable will be set is if the user filled out the form and clicked submit. then it does the check login stuff. this is actually a very common thing for people to do

[Drezek]

very simple i have no idea why i didnt think of that thanks a bunch

[Drezek]

<?php
if (isset($_POST['username'])
{
echo "fsaf";
}
else
{
echo "<form name="login" method="post" action="index.php">";
echo "<input name="username" type="text" id="username">";
echo "<font color="#A4A4A4"><h3><center><bold>PASSWORD</bold></center></h3></font>";
echo "<input name="password" type="password" id="password"><br>";
echo "<center><input type="submit" name="Submit" value="Login"></form></center>";
}
?>

 

whats wrong with this

[cags]

The syntax highlighting shows you exactly whats wrong, you start the echo statement with a double quote, so as soon as it encouners another double quote it thinks that string is finished you need to either swap some of the quotes to single quotes or you need to escape the double quoets.

 

Example:

echo "<form name=\"login\" method=\"post\" action=\"index.php\">";