[SOLVED] matching numbers inside ( )

[Michdd]

I know I can match numbers by just [0-9]+, so I thought matching numbers inside ( ) would be something like

/\([0-9]+\)/

, but that doesn't work  Can someone correct me please?

[cags]

Have you got an example pattern that it doesn't work on, because that looks right to me.

[Michdd]

preg_match_all("/\([0-9]+\)/", '(S2O3)-2', $matches);
print_r($matches);

 

Output:

Array
(
    [0] => Array
        (
        )

)

[cags]

The pattern doesn't match your original specification, you wanted numbers between brackets. What you have is a letter and 3 numbers surrounded by brackets. Therefore it doesn't match. What EXACTLY do you need to match?

[Michdd]

I need to replace (using preg_replace()) all numbers inside of ( ) with _{number here} where "number here" is the number matched.

[cags]

Highly doubt it's the most elegant solution, but how about this..

 

echo preg_replace("~(\(.*?)(\d+)(.*?\))~", '$1<sub>$2</sub>$3', '(S203)-2');

[Michdd]

That won't work because the format isn't always non-number, number, non-number. Even in the example I posted it isn't.

[salathe]

Given the input string "(S2O3)-2", what do you want to be captured (ie, what should/would the matches array look like) exactly?

[thebadbad]

I would probably go with preg_replace_callback() (with nested preg_replace() calls):

 

<?php
$str = '(S2O3)-2';
$str = preg_replace_callback(
'~\([^)]*\)~',
create_function(
	'$matches',
	'return preg_replace(\'~[0-9]+~\', \'<sub>$0</sub>\', $matches[0]);'
),
$str
);
echo $str;
?>

[Michdd]

That worked perfectly, thanks. I was gonna use preg_replace_callback() also, but I was going to do it in a different fashion.

[cags]

Whlist thebadbad's solution is perhaps the better solution, did you even try mine rather disgard it out of hand? Whats the fact it won't always be non-number, number, non-number. Got to do with it, my pattern captures the first bracket and any other character (0 or more meaning there doesn't have to be one) followed by a number, followed by 0 or more characters followed by a closing bracket, it should work fine on your example.

[thebadbad]

Whlist thebadbad's solution is perhaps the better solution, did you even try mine rather disgard it out of hand? Whats the fact it won't always be non-number, number, non-number. Got to do with it, my pattern captures the first bracket and any other character (0 or more meaning there doesn't have to be one) followed by a number, followed by 0 or more characters followed by a closing bracket, it should work fine on your example.

 

That's a capital o in his sample, not a zero. Easy mistake to make though