Jump to content

[SOLVED] another sql error...


mike12255

Recommended Posts

So i cant figure out what or how, but aparently in my sql i have a constent escaping the string can anyone spot the error..?? Name is defined earlier it is passed as a paramiter through the function.

 

<?php
$x=2;
$z=1;
while($x != 0){
$temp2 = $name.$x;
$get = "SELECT content FROM " .NC_DB_PREFIX." content WHERE name ='".$temp2"'";
$res = mysql_query($get) or die (mysql_error());
$row = mysql_fetch_assoc($res);
?>

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.