mike12255 Posted October 25, 2009 Share Posted October 25, 2009 So i tried using "DEFINE" for the first time and im using the variables i defined to connect but it reports back this error: Warning: mysql_query(): 11 is not a valid MySQL-Link resource in /home/content/p/p/f/ppffffpp/html/avalancheatblue.com/nc-cms/system/modules/storage/mysql.php on line 25 Can anyone look at the function and find out why this is? <?php function nc_save_content ($name, $data) { $nc_db_link = mysql_connect(NC_DB_HOST, NC_DB_USER, NC_DB_PASSWORD); $nc_db_link = nc_db_link($nc_db_link, NC_DB_DATABASE); $x=3; while($x != 0){ nc_check_content($name.$x, "Edit Me History" . $x);//line 9-14 making sure the history exists (if not creates it)[function is internal] $x--; } //Now start backwards and work from 2-0 moving files for history $x=2; $z=1; while($x != 0){ $temp2 = $name.$x; $get = "SELECT content FROM " .NC_DB_PREFIX."content WHERE name ='".$temp2."'"; $res = mysql_query($get,$nc_db_link) or die (mysql_error()); $row = mysql_fetch_assoc($res); $temp = $x + 1; $insert = "UPDATE ".NC_DB_PREFIX."content SET content='".$row['content']."' WHERE name='".$name.$temp."'"; $res2 = mysql_query($insert,$nc_db_link) or die (mysql_error()); $x--; } //one last thing move the current entry to 1 before we overwrite it!!! $sql = mysql_query("SELECT content FROM " .NC_DB_PREFIX."content WHERE name ='".$name."'",$nc_db_link) or die (mysql_error()); $row = mysql_fetch_assoc($sql); $insert = mysql_query ("UPDATE ".NC_DB_PREFIX."content SET content='".$row['content']."' WHERE name='".$name."1"."'",$nc_db_link) or die (mysql_error()); nc_check_content ($name, "Edit Me!"); // Make sure database entry exists $nc_db_result = mysql_query("UPDATE ".NC_DB_PREFIX."content SET content='".nc_db_escape($data)."' WHERE name='".$name."'", $nc_db_link); if(!$nc_db_result) // Check for query errors { nc_report_error("MySQL reported: ".mysql_error()); exit(); } mysql_close($nc_db_link); // Close connection } ?> Quote Link to comment Share on other sites More sharing options...
Mchl Posted October 25, 2009 Share Posted October 25, 2009 What does nc_db_link() function do? Specifically, what does it return? Quote Link to comment Share on other sites More sharing options...
mike12255 Posted October 25, 2009 Author Share Posted October 25, 2009 here is the nc_db_link function <?php function nc_db_link ($link, $_database) { if ($link) { if (mysql_select_db($_database, $link)) return $link; else { nc_report_error("MySQL reported: ".mysql_error()); exit(); } } else { nc_report_error("MySQL reported: ".mysql_error()); exit(); } } ?> Quote Link to comment Share on other sites More sharing options...
mike12255 Posted October 25, 2009 Author Share Posted October 25, 2009 anyone....? Quote Link to comment Share on other sites More sharing options...
mike12255 Posted October 26, 2009 Author Share Posted October 26, 2009 bumb... Quote Link to comment Share on other sites More sharing options...
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