[SOLVED] Populate form fields from database

[siric]

Hi,

 

I am pulling data from a database to populate a form for editing purposes.  The form includes many radio buttons.

 

Is there a more elegant way to accomplish this than the following -

 

if ($var1 = '1') {
  print "<input type='radio' value='1' checked name='quality'>1<p>;
} else {
  print "<input type='radio' value='1' name='quality'>1<p>;
}

if ($var1 = '2') {
  print "<input type='radio' value='2' checked name='quality'>2<p>;
} else {
  print "<input type='radio' value='2' name='quality'>2<p>;
}
......

 

 

Thanks

 

 

[mrMarcus]

<?php
echo '<input type="radio" value="1" name="quality"'.(($var1 = '1') ? ' checked' : '').'" />';
?>

 

and so on for each $var;

[siric]

<?php
echo '<input type="radio" value="1" name="quality"'.(($var1 = '1') ? ' checked' : '').'" />';
?>

 

and so on for each $var;

 

Thanks.  Will try this.

 

 

[siric]

<?php
echo '<input type="radio" value="1" name="quality"'.(($var1 = '1') ? ' checked' : '').'" />';
?>

 

and so on for each $var;

 

Thanks.  Will try this.

 

 

 

Have tried it and it doe snot work. Button is always unchecked.

[mrMarcus]

does $var1 or $var2 have a value of either 1 or 2?  have you echo'd them out to make sure?

 

post all relevant code (query, form).

[mrMarcus]

my bad, try this:

 

<?php
echo '<input type="radio" value="1" name="quality"'.(($var1 == '1') ? ' checked' : '').'" />';
?>

 

i had given you the wrong comparable (= instead of ==) .. try this code now.

 

EDIT: for the record, i rarely test code that i post.

[siric]

my bad, try this:

 

<?php
echo '<input type="radio" value="1" name="quality"'.(($var1 == '1') ? ' checked' : '').'" />';
?>

 

i had given you the wrong comparable (= instead of ==) .. try this code now.

 

EDIT: for the record, i rarely test code that i post.

 

That was the problem.  I started from an if statement from scratch and realised just before I saw this post.

 

 

Much Thanks.