Help needed with form code for MySQL database on GoDaddy

vixtay · November 13, 2009

Hi everyone,

I am completely new to PHP and trying very hard to teach myself how to use it as I am stepping up to database websites.

I have created an MySQL database on GoDaddy and a duplicate on my laptop with phpmyadmin. Both are ok. I set up a testing server in Dreamweaver for the one on my laptop to try out an input info form and it worked perfectly. I have a connection to the database on localhost and the data from the form inserted into the datbase perfectly.

Now I need to adapt that same form to do exactly the same but input info in my database on GoDaddy.

I have looked on their help section and used the example that they give. But to no joy, I cannot connect to the datbase despite using the correct login details so I am assuming it must be somehting I am doing wrong with the PHP coding. Can someone please take a look at this and tell me where I am going wrong.

Many thanks in anticipation. I have changed the actual details with capitals to show you.

<?php

//Connect To Database

$hostname="HOSTNAME PROVIDED BY GoDADDY.hostedresource.com";

$username="MY USERNAME";

$password="MY PASSWORD";

$dbname="vixtay.db";

$usertable="members";

mysql_connect($hostname,$username, $password) OR DIE ('Unable to connect to database! Please try again later.');

mysql_select_db($dbname);

$sql="INSERT INTO registrants (Name, Telephone, Email, Username, Password)

VALUES

('$_POST[name]','$_POST[telephone]','$_POST','$_POST[username]','$_POST[password]')))";

if($result)

{

while($row = mysql_fetch_array($result))

{

$name = $row["$yourfield"];

echo "Name: ".$name."<br>";

Schlo_50 · November 13, 2009

I just visited the page your trying to process and the error returned was:

Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'vixtay' etc..

That error means that the database 'vixtay.db' doesn't exist. I'd suggest checking your database names.

vixtay · November 13, 2009

I just visited the page your trying to process and the error returned was:

Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'vixtay' etc..

That error means that the database 'vixtay.db' doesn't exist. I'd suggest checking your database names.

I have just logged into it to double check and the database is definately there and called vixtay with one table called members.

What I did notice in the home page was that it had User: [email protected]

That is all I can see everything is correct, i.e. the database name, the Hostname, my password etc.

vixtay · November 13, 2009

This is the info on GoDaddy under MySql:

Status:Setup

Host Name:vixtay.db.4394481.hostedresource.com

Database Name:vixtayDatabase

Version:5.0

Description:Registrations

User Name:vixtay

DSN:Pending Setup

Just to show that there is an actual database and it is all setup.

I could really do with some help here guys as I am going to need a few php forms for this such as login check users etc. and the most important one is this one as it will be linked to a register form.

The one below works perfect on localhost, can anyone help me change this one to work on GoDaddy?

<?php require_once('Connections/vixtay.php'); ?>

<?php

if (!function_exists("GetSQLValueString")) {

function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")

{

$theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;

$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

switch ($theType) {

case "text":

$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";

break;

case "long":

case "int":

$theValue = ($theValue != "") ? intval($theValue) : "NULL";

break;

case "double":

$theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL";

break;

case "date":

$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";

break;

case "defined":

$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;

break;

}

return $theValue;

}

$editFormAction = $_SERVER['PHP_SELF'];

if (isset($_SERVER['QUERY_STRING'])) {

$editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']);

}

if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) {

$insertSQL = sprintf("INSERT INTO registrants (Name, Telephone, Email, Username, Password) VALUES (%s, %s, %s, %s, %s)",

GetSQLValueString($_POST['Name'], "text"),

GetSQLValueString($_POST['Telephone'], "text"),

GetSQLValueString($_POST['Email'], "text"),

GetSQLValueString($_POST['Username'], "text"),

GetSQLValueString($_POST['Password'], "text"));

mysql_select_db($database_vixtay, $vixtay);

$Result1 = mysql_query($insertSQL, $vixtay) or die(mysql_error());

$insertGoTo = "thanks.php";

if (isset($_SERVER['QUERY_STRING'])) {

$insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?";

$insertGoTo .= $_SERVER['QUERY_STRING'];

}

header(sprintf("Location: %s", $insertGoTo));

}

mysql_select_db($database_vixtay, $vixtay);

$query_register = "SELECT Name, Telephone, Email, Username, Password FROM registrants";

$register = mysql_query($query_register, $vixtay) or die(mysql_error());

$row_register = mysql_fetch_assoc($register);

$totalRows_register = mysql_num_rows($register);

?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<head>

<title>Register</title>

<!--

.style2 {font-family: Verdana, Arial, Helvetica, sans-serif; font-weight: bold; }

-->

</style>

</head>

<body>

<form action="<?php echo $editFormAction; ?>" method="post" name="form1" id="form1">

</tr>

<td nowrap="nowrap" align="right"><div align="left" class="style2">Telephone:</div></td>

</tr>

<td nowrap="nowrap" align="right"><div align="left" class="style2">Email:</div></td>

</tr>

<td nowrap="nowrap" align="right"><div align="left" class="style2">Username:</div></td>

</tr>

<td nowrap="nowrap" align="right"><div align="left" class="style2">Password:</div></td>

</tr>

</tr>

</table>

<p>

</p>

</form>

</body>

</html>

<?php

mysql_free_result($register);

?>

siric · November 13, 2009

//Connect To Database

$hostname="HOSTNAME PROVIDED BY GoDADDY.hostedresource.com";

$username="MY USERNAME";

$password="MY PASSWORD";

$dbname="vixtay.db";

$usertable="members";

This is the info on GoDaddy under MySql:

Status:Setup

Host Name:vixtay.db.4394481.hostedresource.com

Database Name:vixtayDatabase

Your script shows the database name as "vixtay.db", yet the GoDaddy information shows the name as "vixtayDatabase".

Schlo_50 · November 13, 2009

vixtay · November 13, 2009

Hi thanks for your suggestions.

I just tried it with VixtayDatabase and by putting . mysql_error()); in and this is what I get:

Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'vixtay'@'72.167.232.219' (using password: YES) in D:\Hosting\4394481\html\insertinfo.php on line 11

Unable to connect to database! Please try again later.Access denied for user 'vixtay'@'72.167.232.219' (using password: YES)

Why am I getting this and in particular D:\hosting\4394481\html\insertinfo.php on line 11 because I have uploaded the insertinfo.php to the host server

siric · November 13, 2009

I do not know the schema for GoDaddy, but usually copying the file from a localhost verbatim will not work.

Try changing the hostname to "localhost".

vixtay · November 13, 2009

Thank you again for the advice. Through trial and error I have no got the form to connect to the database, it seemed I simply had the password wrong!! So I have changed it and now the form is visable here:

http://www.southwalespropertysolutions.com/insertinfo.php

But the form does not input the data into the members table. Can you please take a look below and see why this is and how I correct it. I also want to link to this page when the registration is successful, what do I put in for this and where please:

http://www.southwalespropertysolutions.com/thanks.php

Here is the current code that gets the form to at least be seen.

<?php

//Connect To Database

$hostname="vixtay.db.4394481.hostedresource.com";

$username="vixtay";

$password="password";

$dbname="vixtay";

$usertable="members";

mysql_connect($hostname,$username, $password) or die ("<html><script language='JavaScript'>alert('Unable to connect to database! Please try again later.'),history.go(-1)</script></html>");

mysql_select_db($dbname);

$sql="INSERT INTO MEMBERS (Name, Telephone, Email, Username, Password)

VALUES('$_POST[name]','$_POST[telephone]','$_POST','$_POST[username]','$_POST[password]')))";

if($result)

{

while($row = mysql_fetch_array($result))

{

$name = $row["$yourfield"];

echo "Name: ".$name."<br>";

}

?>

<html>