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You're also not using the correct syntax for updating (I edited my last post already).

 

Thanks again, i inserted it and it looked like this:

$sql = "UPDATE players SET Linked='1' WHERE Name='PN'";
VALUES
('$_POST[fname]')";
mysql_query($sql);

 

I received a error:

Parse error: syntax error, unexpected '"' in /www/110mb.com/s/o/u/t/h/w/e/s/southwestrp/htdocs/link.php on line 31

 

Doing a quick study i commented the two lines that look like this:

	VALUES
('$_POST[fname]')";

Then it worked, but the row still didn't change, Any idea why?

Are you sure the column names in the query are correct (they are case sensitive), and that there is actually a record with the Name 'PN'?

 

Sorry i don't know alot about PHP, I know more about the pawn language, can please explain how do i make it a record??

Based on that screenshot it doesn't look like you have a record with the Name 'PN', so of course no records will be updated.

 

oh, I was a bit confused then, also this is what it looks like now:

$sql = "UPDATE players SET Linked='1' WHERE Name='Linked'";
//VALUES
//('$_POST[fname]')";
mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, 

E_USER_ERROR);

 

Those are commented because everytime i uncomment it i get errors  :shrug:

Yea, those two lines aren't supposed to be there. When I posted the query before that's all that was supposed to be in it, you can completely remove those lines.

 

(Again) Based on that screenshot all I see is 1 record with the Name 'Eric_Wright', and do you even have a column named 'Linked'? I can't tell from the screenshot.

   $sql = "UPDATE players SET Linked='1' WHERE Name='Linked'";
   mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, E_USER_ERROR);

 

You only have one record in the table and the "Name" filed does not contain the string "Linked" it contains the string "Eric_Wright".

 

   $sql = "UPDATE players SET Linked='1' WHERE Name='Linked'";
   mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, E_USER_ERROR);

printf("Query 1: Records updated: %d  ", mysql_affected_rows());

   $sql = "UPDATE players SET Linked='1' WHERE Name='Eric_wright'";
   mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, E_USER_ERROR);

printf("Query 2: Records updated: %d  ", mysql_affected_rows());

What akon song are u reading?

 

I wanna love you =)

 

   $sql = "UPDATE players SET Linked='1' WHERE Name='Linked'";
   mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, E_USER_ERROR);

 

You only have one record in the table and the "Name" filed does not contain the string "Linked" it contains the string "Eric_Wright".

 

   $sql = "UPDATE players SET Linked='1' WHERE Name='Linked'";
   mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, E_USER_ERROR);

printf("Query 1: Records updated: %d  ", mysql_affected_rows());

   $sql = "UPDATE players SET Linked='1' WHERE Name='Eric_wright'";
   mysql_query($sql) or trigger_error(mysql_error() . 'on line: ' . __LINE__, E_USER_ERROR);

printf("Query 2: Records updated: %d  ", mysql_affected_rows());

 

Sorry for the late reply i was busy, anyway Its hard to explain but everybody has there own account, I was testing the database to see if i can the Linked from 0 to 1. People register there account ingame ( SA-MP is the game http://www.sa-mp.com ) And So I want them to link there account online using my website for my game server. So I just don't want it for my name, for the other people too understand? So when you wrote:

WHERE Name='Eric_wright'

I didnt just want it for me only thats why i put %_post from the input box text!

 

edit:

Yes i do have one coll-um  named "Linked"

By the way, there's a topic solved feature, you can mark your topic as solved with the button at the bottom left of the page.

 

Thanks do i have to make a topic for a simple question? ( How do i change php echo function into a color? )

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