Variable as website...

[dannyluked]

Hi,

I have this code;

 <?php
if(!$_POST[id]){
header('Location: HTTP://EXAMPLE.COM');exit;
}else{
}
?>

 

The code works fine! I was just wondering how I can change the 'http://example.com' to a variable that is in a seperate file (config.php)?

I am guessing it is something like this although this code dosent work!

 

 <?php
include "config.php";
if(!$_POST[id]){
header('Location: $thesite');exit;
}else{
}
?>

[Vytas]

header("Location: $thesite");

This should work.

[rajivgonsalves]

you should use double quotes also use isset

 

<?php
include "config.php";
if(!isset($_POST[id])){
header("Location: $thesite");exit;
}else{
}
?>

[mrMarcus]

in theory will work, if done right.  you can't use single-quotes in this situation.  you can use double-quotes as any PHP within double-quotes will be parsed, or you can use concatenation:

 

 <?php
include "config.php";
if(!$_POST[id]){
     header('Location:' . $thesite); exit;
}else{
}
?>

 

-OR-

 

 <?php
include "config.php";
if(!$_POST[id]){
     header("Location: $thesite");exit;
}else{
}
?>

 

all assuming $thesite has been declared in config.php

[dannyluked]

Thanks guys, they all work!

[dannyluked]

Just one question! How do I make it go to $thesite/FOLDER

[mrMarcus]

using concatenation/string operators:

 

 <?php
include "config.php";
if(!$_POST[id]){
     header('Location:' . $thesite . '/FOLDER'); exit;
}else{
}
?>

 

-AND-

 

 <?php
include "config.php";
if(!$_POST[id]){
     header("Location: $thesite/FOLDER"); exit;
}else{
}
?>