MYSQL ERROR CODE

devang23 · December 7, 2009

I keep getting this error code Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'a3213677'@'192.168.0.10' (using password: YES) in /home/a3213677/public_html/workpart2.php on line 5

i have no clue what it means, here is the short script im trying to write

<html><head><title>I'm a GENUIS</title></head>
<body>
<?php

$conn=mysql_connect("mysql4.000webhost.com","*****","*****") or die("try again punk");
$rs = mysql_select_db("a3213677_snorre", $conn) or die("NOOOPE");
$sql="select * from User Table";
$rs=mysql_query($sql,$conn) or die("still nada");;

$list = "<table border=\"1\" cellpadding=\"2\">";
$list.="<tr><th><First Name</th>";
$list.="<th>Last Name</th>";
$list.="<th>UserName</th>";
$list.="<th>PassWord</th></tr>";

while($row= mysql_fetch_array($rs) )
{
$list .= "<tr>";
$list .= "<td>".$row["first_name"]."</td>";
$list .= "<td>".$row["last_name"]."</td>";
$list .= "<td>".$row["username"]."</td>";
$list .= "<td>".$row["password"]."</td>";
$list .= "</tr>";
}
$list .= "<\table";

echo($list);

?>
</body><html>

Mchl · December 7, 2009

This means either username or password you supplied for MySQL connection is incorrect.

devang23 · December 7, 2009

This means either username or password you supplied for MySQL connection is incorrect.

thats the thing though, both are correct...and it matches my username and password that i have for mysql. im working off a 3rd party server. do you know what would be the possible reason its not pickin up the mysql that comes with it.

PFMaBiSmAd · December 7, 2009

On the mysql host you are trying to connect to, the username/password does not have any access. Are you sure the host name you are using is correct for your account? Most shared web hosts have multiple mysql servers.

devang23 · December 7, 2009

ok well i think i changed the name, and no error this time but now what comes up is MY error that i entered in for it

"still nada"

<html><head><title>I'm a GENUIS</title></head>
<body>
<?php

$conn=mysql_connect("mysql4.000webhost.com","a3213677_dolphin","*****") or die("try again punk");
$rs = mysql_select_db("a3213677_snorre", $conn) or die("NOOOPE");
$sql="select * from User Table";
$rs=mysql_query($sql,$conn) or die("[b]still nada[/b]");;

$list = "<table border=\"1\" cellpadding=\"2\">";
$list.="<tr><th><First Name</th>";
$list.="<th>Last Name</th>";
$list.="<th>UserName</th>";
$list.="<th>PassWord</th></tr>";

while($row= mysql_fetch_array($rs) )
{
$list .= "<tr>";
$list .= "<td>".$row["first_name"]."</td>";
$list .= "<td>".$row["last_name"]."</td>";
$list .= "<td>".$row["username"]."</td>";
$list .= "<td>".$row["password"]."</td>";
$list .= "</tr>";
}
$list .= "<\table";

echo($list);

?>
</body><html>

Mchl · December 7, 2009

Instead of:

or die("try again punk");

use

or die(mysql_error());

This will at least display something meaningful.

devang23 · December 7, 2009

Instead of:
or die("try again punk");
use
or die(mysql_error());
This will at least display something meaningful.

atleast im making some kind of progress, thanks for that, but now it said this

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''User Table' Where 1' at line 1

should i post both scripts im working with, so you have a better knowledge of what im doing?

Mchl · December 7, 2009

select * from User Table

What are you trying to do with this?

If table is called User Table (bad idea to have spaces in tablenames) it should be

SELECT * FROM `User Table`

devang23 · December 7, 2009

Im trying to set this up so ppl can input simple info, fistname,lastnight,username,password.....then i wanna store this info into mysql....and then i want to be able to pull the info that was saved and look at it. im learning php and mysql for my business, and i want to set it up online. im kinda new at this, and a little lost, would you like to see both scripts im working with?

devang23 · December 7, 2009

heres what came up when i changed the SELECT

Parse error: syntax error, unexpected T_STRING in /home/a3213677/public_html/workpart2.php on line 10

<html><head><title>I'm a GENUIS</title></head>
<body>
<?php

$conn=mysql_connect("mysql4.000webhost.com","a3213677_dolphin","hello23") or die(mysql_error());
$rs = mysql_select_db("a3213677_snorre", $conn) or die("NOOOPE");
$sql="SELECT * FROM `User Table`;
$rs=mysql_query($sql,$conn) or die(mysql_error());;

$list = "<table border=\"1\" cellpadding=\"2\">";
$list.="<tr><th><First Name</th>";
$list.="<th>Last Name</th>";
$list.="<th>UserName</th>";
$list.="<th>PassWord</th></tr>";

while($row= mysql_fetch_array($rs) )
{
$list .= "<tr>";
$list .= "<td>".$row["first_name"]."</td>";
$list .= "<td>".$row["last_name"]."</td>";
$list .= "<td>".$row["username"]."</td>";
$list .= "<td>".$row["password"]."</td>";
$list .= "</tr>";
}
$list .= "<\table";

echo($list);

?>
</body><html>

Mchl · December 7, 2009

You're missing a " here

$sql="SELECT * FROM `User Table`;

devang23 · December 7, 2009

You're missing a " here
$sql="SELECT * FROM `User Table`;

i tried that it didnt do anything, still says i got osmething wrong in line 10(t_variable)

fenway · December 9, 2009

You're talking about php syntax errors, not mysql problems.

devang23 · December 9, 2009

You're talking about php syntax errors, not mysql problems.

huh its a mysql error tho

<html>

<head>

<title>Adding a User </title>

</head>

<body>

<?php

ini_set('display_errors', '1');

error_reporting(E_ALL);

$conn = mysql_connect("mysql4.000webhost.com","a3213677_dolphin","*********")or die("Try Again Punk");

var_dump($conn);

$db = mysql_select_db("a3213677_snorre",$conn)or die("NOOPE");

$firstname = isset($_POST['firstname']) ? mysql_real_escape_string($_POST['firstname']) : '';

$lastname = isset($_POST['lastname']) ? mysql_real_escape_string($_POST['lastname']) : '';

$username = isset($_POST['username']) ? mysql_real_escape_string($_POST['username']) : '';

$password = isset($_POST['password']) ? mysql_real_escape_string($_POST['password']) : '';

if( (!$firstname) or (!$lastname) or (!$username) or (!$password) ) {

echo <<< EOS

Please enter all new user details

First Name: <input type="text" name="firstname" value="$firstname"><br />

Last Name: <input type="text" name="lastname" value="$lastname"><br />

UserName: <input type="text" name="username" value="$username"><br />

PassWord: <input type="password" name="password" value="$password"><br />

</form>

EOS;

}

else {

$sql = "insert into `User Table` (`first name`,`last name`,username,password) values ('$firstname','$lastname','$username','$password')";

if($result) { echo("New User $username added"); }

}

?>

</body>

</html>

devang23 · December 9, 2009

resource(5) of type (mysql link)

Mchl · December 9, 2009

So what? That's what it's supposed to be.

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MYSQL ERROR CODE

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