php adding inside a string

[Nom Nom]

I was just wondering how would you add a string in a certain point of a string. It's for my web crawler.

 

<?php

//So like, say:

$var2 = "http://domain.co.uk"

$var[0] = "href=\"/folder/\""

/* How would I add $var2 to $var[0] but in the href attribute? I normally wouldn't know what $var[0] equals until it was outputted/*

?>

 

 

Kinda hard to explain, if you need any more explaination, just ask. (:

[rajivgonsalves]

something like this

 

<?php
//So like, say:
$var2 = "http://domain.co.uk";
$var[0] = 'href="/folder/"';

$var[0] = preg_replace('#href="(.*?)"#', "href=\"$var2$1\"", $var[0]);

echo $var[0];


?>

[Nom Nom]

No, it's like um, an array, more than one.

[rajivgonsalves]

I don't get what you mean please elaborate a little further

[Nom Nom]

It is an array, 'cos it's a web crawler. I don't know what any of the parts of the array is. I'm trying to add the domain, into the href so I can click on the link.

 

'tis hard to explain. =/

 

EDIT: well, it is like what you said, just how would I do it to the whole array?

[rajivgonsalves]

this

 

<?php
//So like, say:
$var2 = "http://domain.co.uk";
$var[0] = '<a href="/folder/">test1</a>';
$var[1] = '<a href="/folder/">test2</a>';

$var = preg_replace('#href="(.*?)"#', "href=\"$var2$1\"", $var);

print_r($var);


?>

[Nom Nom]

What is the $1 bit for?

[rajivgonsalves]

$1 stands for the existing matched href in the expression since it could be anything.

[Nom Nom]

Ah thanks. It's working now. (:

[Brandon_R]

If im not mistaken, you want to convert relative to absolute urls?

 

$newurl = str_replace('href="/', $url ,$var[0]);