in_array search problem

[NaGGi]

Looked all search results but didnt quite found what I was looking for and my noob php brain can't figure the php manual out so I'll just ask.

 

I have an array which have another array inside and Id like to searh a value from that array

 

My array:

print_r($product_rows);

gives:

Array ( [0] => Array ( [row_color] => sectiontableentry1 [product_name] => Lattaaa pew
[product_attributes] => [product_sku] => xxxx [product_price] => 45.00 € )

 

Now I have modifer:

$db_sku = xxxx

 

Now I'd like to search if that xxxx value is in that array

 

How that if sentence should be written?

 

Atm my code looks like this but its not working

if (in_array(array($product_sku, $db_sku ),$product_rows) ) { echo found; } else { echo not_found; }

 

Any hints?

[rajivgonsalves]

this should work

if (in_array(array($db_sku ,$product_rows[0]) ) { echo 'found'; } else { echo 'not_found'; }

 

[NaGGi]

That gives an warning and not_found result

 

Warning: Wrong parameter count for in_array() in ...
not_found

 

 

[trq]

if (in_array('xxxx', $product_rows[0])) {
  echo "xxx found";
}

[NaGGi]

if (in_array('xxxx', $product_rows[0])) {
  echo "xxx found";
}

 

Oh this simple thing actually works. That [0] tells that there is array in array or why it works?

 

Problem comes when there is bigger array like [1],[2], etc though.

[ChemicalBliss]

You need a recursive loop/function.

 

<?php

function recur_in_array($array,$string){
   for($i=0;$i<count($array);$i++){
      if(is_array($array[$i])){
         $found = recur_in_array($array[$i],$string);
         if($found === true){
            return $found;
         }
      }else{
         if (in_array($string, $product_rows[0])) {
           return true;
         }
      }
   }
}

if(recur_in_array($array_var) === true){
   echo("xxx found");
}

?>

 

-CB-

[NaGGi]

Ok thanks a lot! Gotta check that loop out if I need it.