Capturing back references from preg_replace as variables

[jamessw]

Is it possible to define a variable within preg_replace? This would allow me to use them later. I've tried things like setting the replacement pattern to '$variable = $1', which I'm not surprised didn't work. Any ideas?

 

[trq]

You can use an array within the replacement argument.

[salathe]

Can you give more details (a quick snippet example) of what you're trying to achieve, even if it doesn't work?

[jamessw]

Here's an example-

 

$string = 'First worked | FAIL   |           ';
$pattern = '%(.+) \| (.+) \| .+%i';
$replacement = '{$first = $1}{$second = $2}';
echo preg_replace($pattern, $replacement, $string);

echo $first;

 

How would I use an array in the replacement pattern?

[jamessw]

Ok. Using the /e at the end of the search pattern, you can have preg_replace execute the code define("THENAME","$1), and then set a variable to that constant.