elseif issue

[jarvis]

Hi,

 

Am probably being thick (not enough coffee yet!!!). Why is the below not working:

$pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
$filename = basename($pageURL);
echo $filename; //debug

if ($filename == 'index.php') {
	echo 'home';
} elseif ($filename == 'about.php') {
	echo 'about';
} elseif ($filename == 'services.php') {
	echo 'services';
} elseif ($filename == 'affiliate.php') {
	echo 'affiliate';
} elseif ($filename == 'links.php') {
	echo 'links';
} else($filename == 'contact.php') {
	echo 'contact';
}

 

The idea is it get the filename from the URL and depending which page, a different image will be shown.

 

Sorry it's a silly question. Your help is appreciated!

 

Many thanks

[trq]

Firstly, else's cannot have an expression, so this line....

 

} else($filename == 'contact.php') {

 

is syntactically incorrect. Have you got a mod_rewrite rule in place to force this file to handle these requests?

[jarvis]

Hi thorpe,

 

No, no rewrite in place. I thought I could just grab the filename, then do a simple statement to match the filename, if it matches, show a particular image!?

[trq]

That makes no sense. If the url is http://yourdomain.com/links.php your server is going to look for a file called links.php (not the script you have posted) etc etc.

[jarvis]

Sorry to sound daft, but if

$pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];	
$filename = basename($pageURL);	
echo $filename; //debug

Can give me the filename, then don't I just need to say if filename = $filename, then show x y or z?

As $filename would be links.php, so don't I just need to say, it $filename is equal to links.php show whatever?

[jarvis]

Solved:

$pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
$filename = basename($pageURL);
#echo $filename; //debug

if ($filename == 'index.php') {
	echo 'home';
} elseif ($filename == 'about.php') {
	echo 'about';
} elseif ($filename == 'services.php') {
	echo 'services';
} elseif ($filename == 'affiliate.php') {
	echo 'affiliate';
} elseif ($filename == 'links.php') {
	echo 'links';
} else {
	echo 'contact';
}

[trq]

Obviously this file is being included within another. You failed to mention that. Always best to provide the relevant information.